JC2 H2 Physics: https://sites.google.com/tmjc.edu.sg/h2phybatch2122
JC2 H1 Physics: https://sites.google.com/tmjc.edu.sg/h1phybatch2122
JC1 H2 Physics: https://sites.google.com/tmjc.edu.sg/h2phybatch2223
JC1 H1 Physics: https://sites.google.com/tmjc.edu.sg/h1phybatch2223
This animation shows the contact force F exerted on object by the banked road. The horizontal component of this force F provides for centripetal force.
Click and drag to pan the view.
This animation shows the blue ball in circular motion. The red arrow indicates the velocity vector of the blue ball.
How will the ball moves when the string breaks and hence the centripetal force on the ball vanishes? Click "break string" to find out.
This animation shows the contact force N exerted on object by the circular track. The weight of the object is always vertically downwards but the normal contact force changes in both magnitude and direction.
Click on "Pause" & "Highest Point" to study the forces when the object is at the highest point of the circular loop.
Click on "Pause" & "Lowest Point" to study the forces when the object is at the lowest point of the circular loop.
Click on "Show resultant force" to show the vector sum of the normal contact force N and weight W.
The puck and 1.0kg mass is connected by an inextensible string. Since the centripetal force is provided by the tension which remains constant. As the puck spins as a higher linear speed, the radius of circular motion needs to increase.
Click on "Show Tension" to observe the direction of the tension force on the puck.
The 3 balls go at different speeds, the outermost ball (ball 1) goes at the highest speed.
The string closest to the pivot point experience the highest tension as it has to provide sufficient tension to hold onto the 3 balls.
As the ride spins faster, the passengers get lifted higher and at a higher angle from the vertical.
In a non-uniform vertical circular motion, there is a continuous conversion of energy between kinetic energy and gravitational potential energy.
The track provides a normal contact force N when the object remains in contact with the track. If the speed of the object is too low and the required magnitude of centripetal force is too small, normal contact force may decrease to zero and the object loses contact - unable to complete the circular motion.
Hence, there exists a minimum speed at which the object will need to have at the highest point so that it continue to stay in contact with the circular track.
Use the dropdown menu to choose the speed of the ball - above minimum speed, minimum speed and below minimum speed. Observe how the object moves around the track and how the normal contact force N varies.
Higher resolution simulation: https://www.glowscript.org/#/user/lim.kai.ming/folder/MyPrograms/program/06CircularVerticalNonUniformHighRes