In order to figure out how much Helium we can make at the end of Big Bang Nucleosynthesis, we first need to know how many of the composite particles we have: mainly neutrons and Deuterium. The remaining total of Helium, Hydrogen, etc. we have at the end of BBN is called the freeze-out abundance, called this because at the end of BBN the universe expanded and cooled to the point where particle interactions are no longer happening and freezes the final abundances to this value. During this time, the universe was hot, dense, and expanding. To consider how many interactions we can get before the universe expands too much, we need to look at the number density of particles at a given time or temperature. The higher the number of particles squished into a box, the more interactions and collisions we should get. However, as the universe expands the box gets larger and limits the number of interactions. We can relate the expansion of the universe, particle interaction rates, and the number density of particles through the Boltzmann Equation, given as follows
We see from this equation that the number density of particles is affected both by the expansion of the universe and the interaction rate between other particles. As the universe expands, the number density goes down; even if the number of particles remains the same, the number density decreases because the universe's expansion is increasing the volume. This also means that the interaction rate also goes down as the universe expands, because the particles will have a smaller and smaller chance of interacting with one another when the volume they're in gets larger and larger.
Particle decoupling occurs when the Hubble Constant (the rate of expansion of the universe) becomes greater than the interaction rate between other particles, indicating that these particles now evolve/interact independently of others. Particle freeze-out occurs when the interaction rate becomes zero, indicating that no more interactions will take place and whatever abundance of particles you have cannot be changed. To continue our conversation on the final freeze-out abundances of elements, we start by looking at when particles in the universe were in simple, harmonious equilibrium with one another.
For simplicity, we will assume all of the particles that are interacting with one another in the Early Universe were in thermal equilibrium, or that they all have the same temperature, T.
Non-relativistic particles interacting in thermal equilibrium have individual number densities, ni, that are described by the Boltzmann Distribution, given in the equation here. One of the types of particles in an interaction is represented by the subscript i with its mass given as mi. There is another term which represents the 'degrees of freedom of particle', or a number quantifying the particle's intrinsic properties, represented as gi. We will give you these values when we need to do some calculations.
There's also one other variable that we need need to introduce, μi, called the chemical potential. This variable tells us how the energy of an interaction changes when particles form or are annihilated. We will go into more detail in the next subsection.
At early times in the universe, particles were also in chemical equilibrium, meaning that particle formation/annihilation processes efficiently occurred in both directions. Mathematically, we can see that process here for Deuterium creation/annihilation.
When particles are in chemical equilibrium, this efficient back and forth of particle creation/annihilation allows us to relate the chemical potentials really neatly: the change in energy from one side of the reaction will equal the change in energy on the other side. Continuing with our Deuterium example, we can write the following chemical equilibrium equation:
This equation is special for the case of chemical equilibrium. The chemical potential does, indeed, depend on the temperature of the universe; at some point in the universe's history, the annihilation/creation processes will only go one way instead of back and forth. This will break that lovely equation we just found.
There are a few things to note about chemical potentials that will help us in figuring out the final distribution of Helium in the universe. Firstly, that the chemical potential of photons, μˠ, is zero. Secondly, that antiparticles have the negative chemical potential of their particle counter-parts.
Think it Through: In the case where a particle and its antiparticle annihilate into photons at chemical equilibrium, does the chemical equilibrium equation for the chemical potentials hold true?
Indeed it does! Anti-matter has the same magnitude of the chemical potential as their matter counterparts but with the opposite sign! Photons have a chemical potential of zero. Setting up the equation, we then see the ingoing particles' chemical potentials cancel and equal to zero, which is exactly what we'd expect for two photons!
We now possess all of the information we need to figure out how many neutrons there were in the early universe compared to protons. We know what's involved in the process of neutron creation/annihilation, but let's assume that the contributions from electrons and neutrinos are too small to care about. Let's take a ratio of the number densities on each side of the process at equilibrium using the Boltzmann distribution, simplifying a little to cancel out some like-terms, to investigate the processes involved.
THE PROCESS:
AT EQUILIBRIUM:
(approximately)
Since this process is at chemical equilibrium, we know that we can enforce μp= μn, which cancels out an annoying term in the exponent of what we found. Additionally, it turns out that gn= gp, allowing us to simplify this picture even more. The final ratio of neutrons to protons at equilibrium will then only depend on the masses of the particles and the temperature in the following way:
Well this expression is much simpler than the original one! Looking at some of these terms, we see a ratio of the neutron and proton masses. These masses are very similar, so we can take yet another approximation to say that this ratio is 1! Looking at the terms in the exponent, we see that there is a term that depends on the difference between the neutron and proton masses. We can recognize this as the binding energy for a neutron. Because this term is in an exponent, this term will have a large contribution. We can't take the same approximation of the masses as before and need to leave it as-is. Defining Q to be the neutron binding energy, 1.30 MeV, let's re-write our equation to its final form.
Wow! It turns out this expression is a lot simpler than we initially thought. All we need to know to figure out the ratio of protons to neutrons at chemical equilibrium is the temperature of the universe! In general, this is a pretty difficult feat to do. Luckily, scientists have calculated it for us! We can see an informative graph to the side here on when equilibrium should occur: sometime in the middle of neutron-proton decoupling. Looking at the graph, I'd say a value of T = 0.65MeV is a reasonable guess. Plugging this inference into the equation, we find the following ratio rounded to whole numbers:
At equilibrium, there are 7 protons for every 1 neutron.
Let's try to get a very rough estimate of the freeze-out abundance of Helium. If we ignore neutron decay and the formation of the other elements along the way to Helium, we can say that every neutron that existed will be in a Helium atom. Helium atoms are made up of 2 neutrons and 2 protons, though. We show this ratio visually in this figure and circle what would be encapsulated into a Helium atom, where the remaining protons live their lives as Hydrogen. In total, the ratio of Helium to Hydrogen atoms in the universe should then be something like 1:12. Helium is about 4 times more massive than Hydrogen, so the mass ratio of Helium to Hydrogen in the universe should then be about 1:3. Translating from ratios to percentages, roughly 7% of the universe's atoms are Helium and 25% of the total mass of the atoms in the universe is in the form of Helium.
As mentioned in the previous section, we're in a race against time before all of the neutrons in the universe decay away and the formation of Helium relies on the production of Deuterium. Not all neutrons will fuse with a proton to become a Deuterium atom. Cosmologists call having a limited number of Deuterium atoms to fuse into heavier elements the Deuterium Bottleneck.
If we followed the same procedures to find the abundances of Deuterium, protons, and neutrons at chemical equilibrium, we would arrive at the following expression:
THE PROCESS:
AT EQUILIBRIUM:
(approximately)
This becomes trickier because we need to figure out the number densities of all of these particles at this new equilibrium: we can't use our previous results to help us! We would need to solve for each Boltzmann equation, know how to characterize the interaction rate between particles in the early universe, and take into account the decay of neutrons in the formation of Deuterium. Calculations like these are beyond the scope of this course. But know that this can get pretty challenging! Cosmologists can only calculate these quantities numerically using computers.
And just like that, we've formed the atomic building blocks of the universe! The universe is mostly composed of Hydrogen and Helium. There are other processes, though, that make heavier elements. If the universe was made up only of these two elements, we wouldn't even exist! Let's investigate some of the processes that make the other elements in the next page: How to make elements heavier than Helium.