Solution:

Given: 

B = 4.5 T, 

r = 8 cm = 0.08 m, 

θ = 0° (perpendicular)

Area, A = πr²

Using the formula:

ΦB = BAcos θ: ΦB = (4.5 T) * (π * (0.08 m)²) * cos(0°) 

Answer:

ΦB = (4.5 T) * (π * (0.08 m)²) * cos(0°)

      = 4.5 * π * (0.0064) * 1

      ≈ 0.0901 Wb 

Solution:

Given: 

B = 0.6 T, 

Length (l) = 0.35 m, 

Width (w) = 0.25 m, 

θ = 30°

Area, A = lw

Using the formula:

 ΦB = BAcos θ: 

Answer:

ΦB = (0.6 T) * (0.35 m * 0.25 m) * cos(30°)

      = 0.6 * 0.0875 * √3

      ≈ 0.0901 Wb 

Solution:

Given: 

B = 0.9 T, 

Side length (s) = 0.2 m, 

θ = 45°

Area, A = s²

Using the formula: 

ΦB = BAcos θ: 

Answer:

ΦB = (0.9 T) * (0.2 m * 0.2 m) * cos(45°)

      = 0.9 * 0.04 * √2

      ≈ 0.0506 Wb