3×(4+5)

Step 1: First, apply the distributive property.

3×(4+5)=3×4+3×5

Step 2: Now, perform the individual multiplications.

=12+15

Step 3: Add the results.

27

3×(4+5)=27, and we see that applying the distributive property gives us the same result as directly adding 

4+5 first and then multiplying.

2×(5+3)

Step 1: Distribute the 2 across both 5 and 3.

2×(5+3)=2×5+2×3

Step 2: Multiply each term:

2×5=10and2×3=6

Step 3: Add the results

10+6=16

So, 

16

2×(5+3)=16.

x×(y+z)

Step 1: Apply the distributive property.

x(y+z)=x×y+x×zx×(y+z)=x×y+x×z

That’s it! Now, instead of multiplying xx by the whole expression (y+z)(y+z), you multiply xx by each term separately.