F2(g) = pale yellow
Cl2(g) = green/yellow
Br2(I) = orange/brown
I2(s) = black
The colour gets darker and changes from gas to solid as it goes down the group
Melting point generally increases down the group. This is because of the increase in van der Waal's forces. Thus volatility decreases down the group
Atomic radius increases down Group 17 from top to bottom
Reactivity decreases down the group. This is because the force of attraction between the nucleus and the outer electrons gets further apart
Electronegativity decreases down the group. This is because the force of attraction between the nucleus and the outer electrons gets further apart
The volatility of the Group 17 elements decrease down the group due to the increse the numnber of electrons
Decreases. F2 has the highest oxidising power
Increases. F2 has the lowest reducing power
Cl2 + 2NaBr = 2NaCl + Br2
Br2 + 2NaI = 2NaBr + I2
Halogens dissolve well in cyclohexane
purple- I2
Orange- Br2
Pale green- Cl2
H2 + F2 = 2HF, Explosive, dark environment
H2 + Cl2 = 2HCl, Explosive, sunlight
H2 + Br2 = 2HBr, slowly on heating
H2 + I2 = 2HI, equilibrium mixture
Thermal stability decreases down the group because bond length increases and bond energy decreases
Halide ions can be tested using Silver Nitrate solution. The test solution is made using a few drops of dilute nitric acid, followed by a few drops of silver nitrate solution. Different colored solutions can be formed.
NaCl + H2SO4 = NaHSO4 + HCl
NaBr + H2SO4 = NaHSO4 + HBr, HBr and the rest below will be further oxidized
2HBr + H2SO4 = Br2 + SO2 + 2H2O, reddish brown gas is observed
NaI + H2SO4 = NaHSO4 + HI
2HI + H2SO4 = I2 + SO2 + 2H2O
6HI + H2SO4 = 3I2 + S + 4H2O
8HI + H2SO4 = 4I2 + H2S + 4H2O
Yellow solid,S
Rotten egg smell, H2S, product of reduction reaction
Purple vapour, I2
sulfuric acid are oxidizing agents/ gets reduced
Cl2 in cold alkali (15*c)
Cl2 + 2NaOH = NaCl + NaClO + H20
Cl2 in hot alkali (70*c)
3Cl2 + 6NaOH = 5NaCl + NaClO3 + 3H2O
Group 17 chapter revision