Project 20: Calculating Mean Absolute Deviation

Intro Problem: Suppose we asked 10 of your classmates how much they spent on their last haircut and obtained the following values:

5, 0, 50, 70, 100, 10, 30, 40, 140, 25

We know that the average (mean) haircut cost is $47 but how much do students typically deviate from this amount?  For this question, we are interested in how "spread" out the dataset is.

There are a few different measures we could use (range, interquartile range, and absolute mean deviation).  The absolute mean deviation is $34.40 which tells us the typical difference from a classmates' haircut cost to the average of $47.  This shows us that the haircut costs vary widely.

An explanation for the absolute mean deviation is given below.

Project 20: Variable 'dataset' has been initialized.  The variable dataset is an array of values.  There is also a working method called getAverage(array).

getAverage returns the average of the values in the array.

Task: Appropriately initialize the value of 'amd' that represents the absolute mean deviation for dataset.

**If your code works for 5 test cases in a row, you can enter your e-mail address.

Universal Computational Math Methods:

pow(5,2) returns 25.0

abs(-3.0) returns 3

sqrt(49.0) returns 7.0