1) Y = -2x^2 + 8x + 5

What is the maximum value of the quadratic?

Initialize the value of 'x' and 'y' below that represents the x-y coordinate of the highest point on the graph.

2) Y = -2(x+3)^2 + 11

Convert this equation of this quadratic to standard form (in the form y = ax^2 + bx + c)

Initialize the values of 'a', 'b', and 'c' below.

3) Y = 2(x+3)(x-5)

Convert this equation of this quadratic to standard form (in the form y = ax^2 + bx + c)

Initialize the values of 'a', 'b', and 'c' below.

4) Y = -3x^2 + 9x + 12

Y has two zeros (x-intercepts).  Use the quadratic formula to find them:

Initialize the values of 'zero1' and 'zero2'.  

Note: be sure to input zero1 as the smaller zero (the x-intercept on the left) and zero2 as the larger zero (the x-intercept on the right)