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1 decimal integer ring cycle of many

Quantum Field Fractal Polarization Math Constants

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S=∈(P/Θ)cn

S represents ∈(P/Θ)cn

3⅄Pn1/Θn1cn that path 3⅄ of Pn1/Θn1cn differ from paths 2⅄Pn1/Θn2cn and 1⅄Pn2/Θn1cn based on cn of theta Θn variable and variable of the sequential set with no steps

Path 1⅄S=Pn2/Θn1cn

1⅄Sn1=Pn2/Θn1cn=(Pn2/Θn1cn)=(3/0)=0

1⅄Sn2=Pn3/Θn2cn=(Pn3/Θn2cn)=(5/1)=5

1⅄Sn3=Pn4/Θn3cn=(Pn4/Θn3cn)=(7/0.5)=14

1⅄Sn4=Pn5/Θn4cn=(Pn5/Θn4c1)=(11/0.^6)=18.^3 or 18.3 and 1⅄Sn4=Pn5/Θn4cn=(Pn5/Θn4c2)=(11/0.^66)=18.^6 or 18.6 and so on for cn variants of 1⅄Sn4

1⅄Sn5=Pn6/Θn5cn=(Pn6/Θn5cn)=(13/0.6)=21.^6 or 21.6

1⅄Sn6=Pn7/Θn6cn=(Pn7/Θn6cn)=(17/0.625)=27.2

1⅄Sn7=Pn8/Θn7cn=(Pn8/Θn7cn)=(19/0.^615384)=^30.8750 or 30.8750308750

1⅄Sn8=Pn9/Θn8cn=(Pn9/Θn8cn)=(23/0.^619047)=^37.1538833077294615756154217692679231140769602308063846525384986923448461910000371538833077294615756154217692679231140769602308063846525384986923448461910000

37.1538833077294615756154217692679231140769602308063846525384986923448461910000371538833077294615756154217692679231140769602308063846525384986923448461910000371538833077294615756154217692679231140769602308063846525384986923448461910000371538833077294615756154217692679231140769602308063846525384986923448461910000

1⅄Sn9=Pn10/Θn9cn=(Pn10/Θn9cn)=(29/0.6^1764705882352941)=46.9523809523809525151020408163265309955296404275996123681799 extended shell continues with a quotient decimal stem cycle potential having the probability based on divisor or 61,764,705,882,352,941 or less digits determined by this cn variable

1⅄Sn10=Pn11/Θn10cn=(Pn11/Θn10cn)=(31/0.6^18)=^50.16181229773462783171521035598705 or 50.1618122977346278317152103559870550.16181229773462783171521035598705 and so on . . . for 1⅄Sn10c1, 1⅄Sn10c2, 1⅄Sn10c3 infinitely

and so on for cn variables of ∈1⅄Sn

Path 2⅄S=Pn1/Θn2cn

2⅄Sn1=Pn1/Θn2cn=(Pn1/Θn2cn)=(2/1)=2

2⅄Sn2=Pn2/Θn3cn=(Pn2/Θn3cn)=(3/0.5)=6

2⅄Sn3=Pn3/Θn4cn=(Pn3/Θn4cn)=(5/0.^6)=8.^3 or 8.3

2⅄Sn4=Pn4/Θn5cn=(Pn4/Θn5cn)=(7/0.6)=11.^6 or 11.6 or 11.66 or 11.666 and so on

2⅄Sn5=Pn5/Θn6cn=(Pn5/Θn6cn)=(11/0.625)=17.6

2⅄Sn6=Pn6/Θn7cn=(Pn6/Θn7cn)=(13/0.^615384)=^21.1250 or 21.1250211250 and so on . . . 2⅄Sn6c1, 2⅄Sn6c2, 2⅄Sn6c3 infinitely

while 2⅄Sn6=Pn6/Θn7c2=(13/0.^615384615384)=^21.1250000000 or 21.1250000000211250000000 and so on . . .

2⅄Sn7=Pn7/Θn8cn=(Pn7/Θn8cn)=(17/0.^619047)=^27.4615659231043846428461813077197692582307966923351538736154120769505384890000 or 27.4615659231043846428461813077197692582307966923351538736154120769505384890000274615659231043846428461813077197692582307966923351538736154120769505384890000 and so on . . .

2⅄Sn8=Pn8/Θn9cn=(Pn8/Θn9cn)=(19/0.6^1764705882352941)=30.76190476190476199265306122448979616948493683187560810329029571012078505701989250510700492481874049078191883281544902128167285566318767985239863522815527576875800541377697838692763451555327158169800337777 extended shell continues with a quotient decimal stem cycle potential having the probability based on divisor or 61,764,705,882,352,941 or less digits determined by this cn variable

2⅄Sn9=Pn9/Θn10cn=(Pn9/Θn10cn)=(23/0.6^18)=^37.21682847896440129449838187702265 or 37.216828478964401294498381877022653721682847896440129449838187702265 and so on for 2⅄Sn9c1, 2⅄Sn9c2, 2⅄Sn9c3 infintely

2⅄Sn10=Pn10/Θn11cn=(Pn10/Θn11cn)=(29/0.^6179775280878651685393258764044943820224719101123595505)

and so on for cn variables of ∈2⅄Sn

Path 3⅄S=Pn1/Θn1cn

3⅄Sn1=Pn1/Θn1cn=(Pn1/Θn1cn)=(2/0)=0

and so on for cn variables of ∈2⅄Sn and the variants of Θncn variables

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