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1 decimal integer ring cycle of many

Quantum Field Fractal Polarization Math Constants

nemeth braille printable arx calc

pronounced why phi prime quotients

ᐱ Y φ Θ P Q Ψ

condensed matter

Y Phi Theta Prime Q Quotients Base Numerals 1dir 2dir 3dir cdir

numer nu mer numerical nomenclature & arcs

Given H=∈2⅄(Q/Θ)cn

The definition of Q variable should be accurate to its defining base path where 1⅄Q and 2⅄Q, differ from prime base just as φ and Θ differ in paths 1⅄ and 2⅄ of Y base.

so

H=∈2⅄(1⅄Qn1/Θn2)cn

and

H=∈2⅄(2⅄Qn1/Θn2)cn

then

Hn1 of 2⅄(1⅄Qn1/Θn2)=(1.5/1)

Hn2 of 2⅄(1⅄Qn2/Θn3)=(1.^6/0.5)

Hn3 of 2⅄(1⅄Qn3/Θn4)=(1.4/0.^6)

Hn4 of 2⅄(1⅄Qn4/Θn5)=(1.^571428/0.6)

Hn5 of 2⅄(1⅄Qn5/Θn6)=(1.^18/0.625)

Hn6 of 2⅄(1⅄Qn6/Θn7)=(1.^307692/0.^615384)

Hn7 of 2⅄(1⅄Qn7/Θn8)=(1.^1176470588235294/0.^619047)

Hn8 of 2⅄(1⅄Qn8/Θn9)=(1.^210526315789473684/0.6^1764705882352941)

then

if H=∈2⅄(1⅄Qn1/Θn2)cn

and

H=∈2⅄(2⅄Qn1/Θn2)cn

then

Hn1 of 2⅄(2⅄Qn1/Θn2)=(0.^6/1)

Hn2 of 2⅄(2⅄Qn2/Θn3)=(0.6/0.5)

Hn3 of 2⅄(2⅄Qn3/Θn4)=(0.^714285/0.^6)

Hn4 of 2⅄(2⅄Qn4/Θn5)=(0.^63/0.6)

Hn5 of 2⅄(2⅄Qn5/Θn6)=(0.^846153/0.625)

Hn6 of 2⅄(2⅄Qn6/Θn7)=(0.^7647058823529411/0.^615384)

Hn7 of 2⅄(2⅄Qn7/Θn8)=(0.^894736842105263157/0.^619047)

Hn8 of 2⅄(2⅄Qn8/Θn9)=(0.^8260869565217391304347/0.6^1764705882352941)

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