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1 decimal integer ring cycle of many

Quantum Field Fractal Polarization Math Constants

nemeth braille printable arx calc

pronounced why phi prime quotients

ᐱ Y φ Θ P Q Ψ

condensed matter

Y Phi Theta Prime Q Quotients Base Numerals 1dir 2dir 3dir cdir

numer nu mer numerical nomenclature & arcs

Given F=∈2⅄(Θ/Q)cn

The definition of Q variable should be accurate to its defining base path where 1⅄Q and 2⅄Q, differ from prime base just as φ and Θ differ in paths 1⅄ and 2⅄ of Y base.

so

F=∈2⅄(Θn1/1⅄Qn2)cn

and

F=∈2⅄(Θn1/2⅄Qn2)cn

then

Fn1 of 2⅄(Θn1/1⅄Qn2)=(0/1.^6)

Fn2 of 2⅄(Θn2/1⅄Qn3)=(1/1.4)

Fn3 of 2⅄(Θn3/1⅄Qn4)=(0.5/1.^571428)

Fn4 of 2⅄(Θn4/1⅄Qn5)=(0.^6/1.^18)

Fn5 of 2⅄(Θn5/1⅄Qn6)=(0.6/1.^307692)

Fn6 of 2⅄(Θn6/1⅄Qn7)=(0.625/1.^1176470588235294)

Fn7 of 2⅄(Θn7/1⅄Qn8)=(0.^615384/1.^210526315789473684)

if F=∈2⅄(Θn1/1⅄Qn2)cn

and

F=∈2⅄(Θn1/2⅄Qn2)cn

then

Fn1 of 2⅄(Θn1/2⅄Qn2)=(0/0.6)

Fn2 of 2⅄(Θn2/2⅄Qn3)=(1/0.^714285)

Fn3 of 2⅄(Θn3/2⅄Qn4)=(0.5/0.^63)

Fn4 of 2⅄(Θn4/2⅄Qn5)=(0.^6/0.^846153)

Fn5 of 2⅄(Θn5/2⅄Qn6)=(0.6/0.^7647058823529411)

Fn6 of 2⅄(Θn6/2⅄Qn7)=(0.625/0.^894736842105263157)

Fn7 of 2⅄(Θn7/2⅄Qn8)=(0.^615384/0.^8260869565217391304347)

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