Swap two numbers without temporary variables

Solution

#include <iostream>

using namespace std;

int main(int argc, char* argv[])

{

int a = 0x07FFFFFF;

int b = 3;

cout << "a: " << a << " b: " << b << endl;

#if 0 // Method one

a = a^b;

b = a^b;

a = a^b;

#else // Method two

a = a + b;

b = a - b;

a = a - b;

#endif

cout << "a: " << a << " b: " << b << endl;

return 0;

}