A binary search tree relies on the property that keys that are less than the parent are found in the left subtree, and keys that are greater than the parent are found in the right subtree. We will call this the bst property. As we implement the Map interface as described above, the bst property will guide our implementation. Figure 1 illustrates this property of a binary search tree, showing the keys without any associated values. Notice that the property holds for each parent and child. All of the keys in the left subtree are less than the key in the root. All of the keys in the right subtree are greater than the root.
Figure 1: A Simple Binary Search Tree
Now that you know what a binary search tree is, we will look at how a binary search tree is constructed. The search tree in Figure 1 represents the nodes that exist after we have inserted the following keys in the order shown: 70,31,93,94,14,23,73. Since 70 was the first key inserted into the tree, it is the root. Next, 31 is less than 70, so it becomes the left child of 70. Next, 93 is greater than 70, so it becomes the right child of 70. Now we have two levels of the tree filled, so the next key is going to be the left or right child of either 31 or 93. Since 94 is greater than 70 and 93, it becomes the right child of 93. Similarly 14 is less than 70 and 31, so it becomes the left child of 31. 23 is also less than 31, so it must be in the left subtree of 31. However, it is greater than 14, so it becomes the right child of 14.
To implement the binary search tree, we will use the nodes and references approach similar to the one we used to implement the linked list, and the expression tree. However, because we must be able create and work with a binary search tree that is empty, our implementation will use two classes. The first class we will call BinarySearchTree
, and the second class we will call TreeNode
. The BinarySearchTree
class has a reference to the TreeNode
that is the root of the binary search tree. In most cases the external methods defined in the outer class simply check to see if the tree is empty. If there are nodes in the tree, the request is just passed on to a private method defined in the BinarySearchTree
class that takes the root as a parameter. In the case where the tree is empty or we want to delete the key at the root of the tree, we must take special action. The code for the BinarySearchTree
class constructor along with a few other miscellaneous functions is shown in Listing 1.
Listing 1
class BinarySearchTree: def __init__(self): self.root = None self.size = 0 def length(self): return self.size def __len__(self): return self.size def __iter__(self): return self.root.__iter__()
The TreeNode
class provides many helper functions that make the work done in the BinarySearchTree
class methods much easier. The constructor for a TreeNode
, along with these helper functions, is shown in Listing 2. As you can see in the listing many of these helper functions help to classify a node according to its own position as a child, (left or right) and the kind of children the node has. The TreeNode
class will also explicitly keep track of the parent as an attribute of each node. You will see why this is important when we discuss the implementation for the del
operator.
Another interesting aspect of the implementation of TreeNode
in Listing 2 is that we use Python’s optional parameters. Optional parameters make it easy for us to create a TreeNode
under several different circumstances. Sometimes we will want to construct a new TreeNode
that already has both aparent
and a child
. With an existing parent and child, we can pass parent and child as parameters. At other times we will just create a TreeNode
with the key value pair, and we will not pass any parameters for parent
or child
. In this case, the default values of the optional parameters are used.
Listing 2
class TreeNode: def __init__(self,key,val,left=None,right=None, parent=None): self.key = key self.payload = val self.leftChild = left self.rightChild = right self.parent = parent def hasLeftChild(self): return self.leftChild def hasRightChild(self): return self.rightChild def isLeftChild(self): return self.parent and self.parent.leftChild == self def isRightChild(self): return self.parent and self.parent.rightChild == self def isRoot(self): return not self.parent def isLeaf(self): return not (self.rightChild or self.leftChild) def hasAnyChildren(self): return self.rightChild or self.leftChild def hasBothChildren(self): return self.rightChild and self.leftChild def replaceNodeData(self,key,value,lc,rc): self.key = key self.payload = value self.leftChild = lc self.rightChild = rc if self.hasLeftChild(): self.leftChild.parent = self if self.hasRightChild(): self.rightChild.parent = self
Now that we have the BinarySearchTree
shell and the TreeNode
it is time to write the put
method that will allow us to build our binary search tree. The put
method is a method of the BinarySearchTree
class. This method will check to see if the tree already has a root. If there is not a root then put
will create a new TreeNode
and install it as the root of the tree. If a root node is already in place then put
calls the private, recursive, helper function _put
to search the tree according to the following algorithm:
TreeNode
object and insert the object at the point discovered in the previous step.Listing 3 shows the Python code for inserting a new node in the tree. The _put
function is written recursively following the steps outlined above. Notice that when a new child is inserted into the tree, thecurrentNode
is passed to the new tree as the parent.
One important problem with our implementation of insert is that duplicate keys are not handled properly. As our tree is implemented a duplicate key will create a new node with the same key value in the right subtree of the node having the original key. The result of this is that the node with the new key will never be found during a search. A better way to handle the insertion of a duplicate key is for the value associated with the new key to replace the old value. We leave fixing this bug as an exercise for you.
Listing 3
def put(self,key,val): if self.root: self._put(key,val,self.root) else: self.root = TreeNode(key,val) self.size = self.size + 1def _put(self,key,val,currentNode): if key < currentNode.key: if currentNode.hasLeftChild(): self._put(key,val,currentNode.leftChild) else: currentNode.leftChild = TreeNode(key,val,parent=currentNode) else: if currentNode.hasRightChild(): self._put(key,val,currentNode.rightChild) else: currentNode.rightChild = TreeNode(key,val,parent=currentNode)
With the put
method defined, we can easily overload the []
operator for assignment by having the__setitem__
method call (see Listing 4) the put method. This allows us to write Python statements likemyZipTree['Plymouth'] = 55446
, just like a Python dictionary.
Listing 4
def __setitem__(self,k,v): self.put(k,v)
Figure 2 illustrates the process for inserting a new node into a binary search tree. The lightly shaded nodes indicate the nodes that were visited during the insertion process.
Once the tree is constructed, the next task is to implement the retrieval of a value for a given key. The get
method is even easier than the put
method because it simply searches the tree recursively until it gets to a non-matching leaf node or finds a matching key. When a matching key is found, the value stored in the payload of the node is returned.
Listing 5 shows the code for get
, _get
and __getitem__
. The search code in the _get
method uses the same logic for choosing the left or right child as the _put
method. Notice that the _get
method returns a TreeNode
to get
, this allows _get
to be used as a flexible helper method for otherBinarySearchTree
methods that may need to make use of other data from the TreeNode
besides the payload.
By implementing the __getitem__
method we can write a Python statement that looks just like we are accessing a dictionary, when in fact we are using a binary search tree, for examplez = myZipTree['Fargo']
. As you can see, all the __getitem__
method does is call get
.
Listing 5
def get(self,key): if self.root: res = self._get(key,self.root) if res: return res.payload else: return None else: return Nonedef _get(self,key,currentNode): if not currentNode: return None elif currentNode.key == key: return currentNode elif key < currentNode.key: return self._get(key,currentNode.leftChild) else: return self._get(key,currentNode.rightChild)def __getitem__(self,key): return self.get(key)
Using get
, we can implement the in
operation by writing a __contains__
method for theBinarySearchTree
. The __contains__
method will simply call get
and return True
if get
returns a value, or False
if it returns None
. The code for __contains__
is shown in Listing 6.
Listing 6
def __contains__(self,key): if self._get(key,self.root): return True else: return False
Recall that __contains__
overloads the in
operator and allows us to write statements such as:
if 'Northfield' in myZipTree: print("oom ya ya")
Finally, we turn our attention to the most challenging method in the binary search tree, the deletion of a key (see Listing 7). The first task is to find the node to delete by searching the tree. If the tree has more than one node we search using the _get
method to find the TreeNode
that needs to be removed. If the tree only has a single node, that means we are removing the root of the tree, but we still must check to make sure the key of the root matches the key that is to be deleted. In either case if the key is not found the del
operator raises an error.
Listing 7
def delete(self,key): if self.size > 1: nodeToRemove = self._get(key,self.root) if nodeToRemove: self.remove(nodeToRemove) self.size = self.size-1 else: raise KeyError('Error, key not in tree') elif self.size == 1 and self.root.key == key: self.root = None self.size = self.size - 1 else: raise KeyError('Error, key not in tree')def __delitem__(self,key): self.delete(key)
Once we’ve found the node containing the key we want to delete, there are three cases that we must consider:
The first case is straightforward (see Listing 8). If the current node has no children all we need to do is delete the node and remove the reference to this node in the parent. The code for this case is shown in here.
Listing 8
if currentNode.isLeaf(): if currentNode == currentNode.parent.leftChild: currentNode.parent.leftChild = None else: currentNode.parent.rightChild = None
Figure 3: Deleting Node 16, a Node without Children
The second case is only slightly more complicated (see Listing 9). If a node has only a single child, then we can simply promote the child to take the place of its parent. The code for this case is shown in the next listing. As you look at this code you will see that there are six cases to consider. Since the cases are symmetric with respect to either having a left or right child we will just discuss the case where the current node has a left child. The decision proceeds as follows:
key
, payload
, leftChild
, and rightChild
data by calling the replaceNodeData
method on the root.Listing 9
else: # this node has one child if currentNode.hasLeftChild(): if currentNode.isLeftChild(): currentNode.leftChild.parent = currentNode.parent currentNode.parent.leftChild = currentNode.leftChild elif currentNode.isRightChild(): currentNode.leftChild.parent = currentNode.parent currentNode.parent.rightChild = currentNode.leftChild else: currentNode.replaceNodeData(currentNode.leftChild.key, currentNode.leftChild.payload, currentNode.leftChild.leftChild, currentNode.leftChild.rightChild) else: if currentNode.isLeftChild(): currentNode.rightChild.parent = currentNode.parent currentNode.parent.leftChild = currentNode.rightChild elif currentNode.isRightChild(): currentNode.rightChild.parent = currentNode.parent currentNode.parent.rightChild = currentNode.rightChild else: currentNode.replaceNodeData(currentNode.rightChild.key, currentNode.rightChild.payload, currentNode.rightChild.leftChild, currentNode.rightChild.rightChild)
Figure 4: Deleting Node 25, a Node That Has a Single Child
The third case is the most difficult case to handle (see Listing 10). If a node has two children, then it is unlikely that we can simply promote one of them to take the node’s place. We can, however, search the tree for a node that can be used to replace the one scheduled for deletion. What we need is a node that will preserve the binary search tree relationships for both of the existing left and right subtrees. The node that will do this is the node that has the next-largest key in the tree. We call this node the successor, and we will look at a way to find the successor shortly. The successor is guaranteed to have no more than one child, so we know how to remove it using the two cases for deletion that we have already implemented. Once the successor has been removed, we simply put it in the tree in place of the node to be deleted.
Figure 5: Deleting Node 5, a Node with Two Children
The code to handle the third case is shown in the next listing. Notice that we make use of the helper methods findSuccessor
and findMin
to find the successor. To remove the successor, we make use of the method spliceOut
. The reason we use spliceOut
is that it goes directly to the node we want to splice out and makes the right changes. We could call delete
recursively, but then we would waste time re-searching for the key node.
Listing 10
elif currentNode.hasBothChildren(): #interior succ = currentNode.findSuccessor() succ.spliceOut() currentNode.key = succ.key currentNode.payload = succ.payload
The code to find the successor is shown below (see Listing 11) and as you can see is a method of theTreeNode
class. This code makes use of the same properties of binary search trees that cause an inorder traversal to print out the nodes in the tree from smallest to largest. There are three cases to consider when looking for the successor:
The first condition is the only one that matters for us when deleting a node from a binary search tree. However, the findSuccessor
method has other uses that we will explore in the exercises at the end of this chapter.
The findMin
method is called to find the minimum key in a subtree. You should convince yourself that the minimum valued key in any binary search tree is the leftmost child of the tree. Therefore the findMin
method simply follows the leftChild
references in each node of the subtree until it reaches a node that does not have a left child.
Listing 11
def findSuccessor(self): succ = None if self.hasRightChild(): succ = self.rightChild.findMin() else: if self.parent: if self.isLeftChild(): succ = self.parent else: self.parent.rightChild = None succ = self.parent.findSuccessor() self.parent.rightChild = self return succdef findMin(self): current = self while current.hasLeftChild(): current = current.leftChild return currentdef spliceOut(self): if self.isLeaf(): if self.isLeftChild(): self.parent.leftChild = None else: self.parent.rightChild = None elif self.hasAnyChildren(): if self.hasLeftChild(): if self.isLeftChild(): self.parent.leftChild = self.leftChild else: self.parent.rightChild = self.leftChild self.leftChild.parent = self.parent else: if self.isLeftChild(): self.parent.leftChild = self.rightChild else: self.parent.rightChild = self.rightChild self.rightChild.parent = self.parent
We need to look at one last interface method for the binary search tree. Suppose that we would like to simply iterate over all the keys in the tree in order. This is definitely something we have done with dictionaries, so why not trees? You already know how to traverse a binary tree in order, using the inorder
traversal algorithm. However, writing an iterator requires a bit more work, since an iterator should return only one node each time the iterator is called.
Python provides us with a very powerful function to use when creating an iterator. The function is calledyield
. yield
is similar to return
in that it returns a value to the caller. However, yield
also takes the additional step of freezing the state of the function so that the next time the function is called it continues executing from the exact point it left off earlier. Functions that create objects that can be iterated are called generator functions.
The code for an inorder
iterator of a binary tree is shown in the next listing. Look at this code carefully; at first glance you might think that the code is not recursive. However, remember that __iter__
overrides the for x in
operation for iteration, so it really is recursive! Because it is recursive over TreeNode
instances the __iter__
method is defined in the TreeNode
class.
def __iter__(self): if self: if self.hasLeftChild(): for elem in self.leftChiLd: yield elem yield self.key if self.hasRightChild(): for elem in self.rightChild: yield elem
At this point you may want to download the entire file containing the full version of the BinarySearchTree
and TreeNode
classes.
(completebstcode)