Embedded Files
Point Mass Analysis
Point Mass Analysis
Point Mass Analysis consists of the equation 2pi*sqrt(r/g)
g=9.8 m/s^2
r=distance from pendulum to CoM, which gives 1.503 as seen in diagram.
Plugging in numbers, you get 2pi*sqrt[(1.503in*1/39.37m)/9.8] which gives an answer of
0.3825 seconds per oscillation.
Inertial Analysis
Inertial Analysis
First convert the lengths from the pendulum to the weights and center of mass from inches to meters, square those results, and then multiply by their weight, and then add everything together. That comes out to the following: (0.156 lb)*(1/2.204kg)*[1.42in*(1/39.37m)]^2+ (0.00397kg)((0.0954)^2+(0.10076)^2+(0.0995)^2+(0.0864)^2+(0.0945)^2).
This gives us Total Inertia, which is 0.000313 in this case.
Then to get our oscillation frequency, divide by gravity which is 9.8 m/s^2, multiplied by Mr, which is the same as total inertia except lengths are not squared, which give a value of 0.00796.
.000313/(9.8*0.00796)=0.00336, and the final step is to multiply by 2pi, which gives a final value of 0.398 seconds per oscillation.
Two-dimensional Simulation Analysis
Two-dimensional Simulation Analysis
The period took 37 frames on a 60 frame per second simulation-37/60=0.616 s
Page updated
Report abuse