We are learning about:
TOPICS
2.3.1. Calorimetry. What Does Heat Do?
2.3.2. Calorimeters and Calorimetry.
2.3.3. Measuring the Quantity of Heat.
Plan and conduct an investigation to provide evidence that the transfer of thermal energy results in a more uniform energy distribution among the components in the system and show the conservation of energy.
Explore the process of transfer of heat energy to develop conceptual or real models to address the issue of energy wastage.
heat changes the temperature, changes the state and does work
calorimeters, principle of calorimetry and its applications
measurement of heat gained or lost
Explain the effects of heat when it flows between the systems and the surroundings.
Design and carry out experiment on principle of calorimetry.
Design and build their own calorimeters.
Interpret the principle of calorimetry and use calorimetric data to calculate enthalpy changes.
VODEO LESSONS
NOTES:
What Does Heat Do?
Heat Changes the Temperature of Objects
If heat is transferred from an object to the surroundings, then the object can cool down and the surroundings can warm up. When heat is transferred to an object by its surroundings, then the object can warm up and the surroundings can cool down.
Heat, once absorbed as energy, contributes to the overall internal energy of the object. One form of this internal energy is kinetic energy; the particles begin to move faster, resulting in a greater kinetic energy. This more vigorous motion of particles is reflected by a temperature increase. The reverse logic applies as well. Energy, once released as heat, results in a decrease in the overall internal energy of the object. Since kinetic energy is one of the forms of internal energy, the release of heat from an object causes a decrease in the average kinetic energy of its particles.
Heat Changes the State of Matter
The addition of heat to a sample of matter can cause solids to turn to liquids and liquids to turn to gases. Similarly, the removal of heat from a sample of matter can cause gases to turn to liquids and liquids to turn to solids. Each of these transitions between states occur at specific temperatures - commonly referred to as melting point temperature, freezing point temperature, boiling point temperature and condensation point temperature.
Heat Does Work
Energy transfer in the form of heat can result in the performance of work upon the system or the surroundings. Devices that utilize heat to do work are often referred to as heat engines. In general, an engine is a device that does work. A heat engine is a device that uses heat transfer as the source of energy for doing work.
The internal combustion engine of an automobile is an example of a heat engine.
Concept of Heat and Temperature
Heat is a form of energy produced by the random motion of its molecules. It remains inside a body in the form of its internal kinetic energy.
Energy transfer that takes place because of a temperature difference is called heat flow or heat transfer, and the energy transferred in this way is called heat.
The measurement of the quantity of heat is called calorimetry.
Temperature is a measure of the average kinetic energy of the particles in an object. When temperature increases, the motion of these particles also increases.
Units of Heat: Joules or calorie (Calorie is mostly used to measure the heat).
Calorie: One calorie is the quantity of heat required to raise the temperature of 1 g of water by 1°C.
1 calorie = 4.2 joules
Calorimetry:
Calorimetry is the field of science that deals with the measurement of the state of a body with respect to the thermal aspects in order to examine its physical and chemical changes. The changes could be physical such as melting, evaporation or could also be chemical such as burning, acid-base neutralization etc.
Principle of calorimetry:
According to the principle of calorimetry, when a body at higher temperature is brought in contact with another body at lower temperature, the heat lost by the hot body is equal to the heat gain by the colder body, provided no heat is allowed to escape to the surroundings.
Heat lost by the hot body = Heat gain by the cold body.
Calorimeter:
The device in which heat measurement can be made by utilising the principle of calorimetry is called a calorimeter
Calorimeter
The principle of mixture is used for measuring specific heat capacity. The vessel in which the mixing is done is called a calorimeter. The calorimeter is usually made of copper. Copper is a good conductor of heat. It will take less heat to provide the mixture to reach into final steady temperature. To avoid the loss of heat to the surrounding air when hot body is placed in the calorimeter, the outside of the calorimeter is polished. The calorimeter is stood on a piece of cork or wool. The wool and the layer of air between the two vessels, tend to reduce the loss f heat by conduction. A cover with small holes for a stirrer and thermometer is also provided. This prevents the loss of heat by convection from the apparatus.
A change of state can be brought about by putting heat into a system or removing it from the system.
The temperature of a system will not change as long as the substance is undergoing a change from solid to liquid or liquid to gas, as well as the reverse.
Heat Capacity:
The quantity of heat required to raise the temperature of a body by one degree centigrade in termed as the heat capacity of the body.
Heat capacity = Amount of heat / Rise in temperature
Unit: J/°C or cal/°C
Specific Heat Capacity:
The specific heat capacity of a substance is defined as the heat required to raise the temperature of unit mass of that substance through 1 °C. It denoted by the symbol c.
Unit: J/(g°C) or J/(kg °C)
Enthalpy: the total amount of energy in a system, including both the internal energy and the energy needed to displace its environment
Principle of calorimetry:
Heat Lost = Heat Gained
The heat transfer in a system is calculated using the formula,
q=mcΔt
Where
q is the measure of heat transfer
m is the mass of the body
c is the specific heat of the body
Δt is the change in the temperature
Heat energy gained or lost = Mass of the substance x Specific heat x Change of temperature.
Q = mcΔT
Q = mc(T1-T2)
What is the difference between Latent Heat and Specific Heat?
• Latent heat is the energy absorbed or released when a substance is undergoing a phase change. Specific heat is the quantity of heat required to raise the temperature of one gram of a substance by one degree Celsius (or one Kelvin) at a constant pressure.
• Specific heat doesn’t apply when a substance is undergoing phase change.
• Specific heat causes temperature change where in latent heat there’s no temperature change involved.
EXERCISE
Water has an unusually high specific heat capacity. Which one of the following statements logically follows from this fact?
Compared to other substances, hot water causes severe burns because it is a good conductor of heat.
Compared to other substances, water will quickly warm up to high temperatures when heated.
Compared to other substances, it takes a considerable amount of heat for a sample of water to change its temperature by a small amount.
Define heat. Give its unit.
Define the term 'calorie'.
Explain the advantages of high specific heat capacity of water with respect to coastal area.
What do you mean by the statement "the specific heat capacity of water is 4200 J/kg °C."?
Why is water used as coolant in motor car radiators?
Draw a neat and labelled diagram of a calorimeter.
Why is the calorimeter made of copper?
Calculate the heat required to raise the temperature of 42 g of water from 50 °C to 60 °C.
8000 J of heat is given to 200 g of copper at 20 °C. What is the final temperature , if the specific heat capacity of copper is 0.4 J/g °C. [ Hint: take final temperature of copper as X °C.]
Numerical Problems
Examples:
Eg.1. What quantity of heat is required to raise the temperature of 450 grams of water from 15°C to 85°C? The specific heat capacity of water is 4.18 J/g°C.
Solution:
Like any problem in physics, the solution begins by identifying known quantities and relating them to the symbols used in the relevant equation. In this problem, we know the following:
Given:
m = 450 g
C = 4.18 J/(g°C)
T initial = 15°C
T final = 85°C
We wish to determine the value of Q - the quantity of heat. To do so, we would use the equation Q = mcΔT. The m and the C are known; the ΔT can be determined from the initial and final temperature.
T = T final - T initial = 85°C - 15°C = 70.°C
With three of the four quantities of the relevant equation known, we can substitute and solve for Q.
Q = mcΔT = (450 g) x (4.18 J/g/°C) x (70.°C)
Q = 131670 J
Q = 1.3x105 J = 130 kJ (rounded to two significant digits)
Eg.2. Calculate the heat given out when a piece of iron of mass 50 g and specific heat capacity 460 J/kg/°C cools from 80°C to 20°C.
Solution:
Given:
Mass of iron (m) = 50g=0.05kg.
Specific heat capacity of iron, (c)=460 J/(kg°C )
Change in temperature = ΔT = (80 - 20)°C = 60°C
Therefore heat energy Q = mcΔT
0.05 x 460 x 60 = 1380 J
Thus the heat given out by the iron piece is 1380 J
Eg. 3. What is the final temperature of the mixture, if 100 g of water at 70 °C is added to 200 g of cold water at 10°C and well stirred?
Solution:
The specific heat capacity of water is 4200 J/kg°C
Let the final temperature of the mixture be T°C
Then change in temperature of hot water = (70 - T)°C
Change in temperature of cold water = (T-10)°C
According to the principle of calorimetry,
Heat lost by hot water = Heat gained by cold water.
mc(70-T)=mc(T-10)
0.1 x c (70-T) = 0.2 x c (T-10)
Cancelling c on both sides, we get
7 - 0.1T=0.2T-2
9=0.3T
T=30
Hence, the final temperature of the mixture is 30°C
Try Questions:
Q1. What quantity of heat is required to raise the temperature of 500 grams of water from 10°C to 80°C? The specific heat capacity of water is 4.2 J/g°C.
Q2. Calculate the heat given out when a piece of steel of mass 120 g and specific heat capacity 420 J/(kg°C) cools from 120°C to 40°C.
Q3. The temperature of 500 g of a substance is raised to 100 °C and it is then placed in 200 g of water at 15°C. If the final steady temperature rises to 21°C, calculate the specific heat capacity of the substance.
[ take c of water equal to 4200 J/kg°C]
Q4. Karma poured 8kg of cold water at 23 °C to 2kg of hot water in a bucket and the final temperature was 37 °C. What was the initial temperature of the hot water? Neglect the heat lost to the surrounding. (Class XI Physics)
Q5. 45g of water at 50 0C in a beaker is cooled when 50g of copper at 18 0 C is added to it. The contents are stirred till a final constant temperature is reduced. Calculate the final temperature. The specific heat capacity of copper is 0.39 J/gK and that of water is 4.2 J/gK. (From sample question paper)
Multiple Choice Questions:
The method of measuring the heat transfer that occurs within a chemical reaction or other physical processes is known as
thermometry
calorimetry
speedometry
none of the option
The heat transfer in a system is calculated using the formula
q=mc+Δt
q=mc/Δt
q=mcΔt
q=m+c/Δt
Calorimetry is performed with the help of a
thermometer
galvanometer
calorimeter
ammeter
This motion of molecules and atoms creates a form of energy known as
mechanical energy
heat energy
potential energy
kinetic energy
The specific heat capacity of iron is
900 J/kg°C
380 J/kg°C
460 J/kg°C
4200 J/kg°C