Compare the brightness of the bulbs in the diagram (assuming they have the same resistance)

A) A > E > B > C = D

B) A > B > E > C = D

C) A = B = C = D = E

D) A = B = C > D = E

E) Other

Solution: A > E > B > C = D.

The current going through A splits at the junction to its right, so it must have more current (and therefore more power) than B and E.

The equivalent resistance of B, C, and D is greater then the resistance of E alone, so more current goes through E than B. So E has great power than B.

The current through B gets split between C and D, so B has greater power than C and D.

C and D are in parallel, so they have equal potential difference and therefore the same power.