In the last lab, we crossed our mutant hermaphrodites to wild type males. By observing the phenotypes of their progeny, we can learn whether our mutant phenotype is dominant or recessive to the wild type phenotype, and whether the gene causing the phenotype is located on an autosome or the X chromosome.
TO DO:
If our gene of interest is not located on the X chromosome, we next need to determine which chromosome it is on.
We can do this by determining whether our gene segregates independently from known reference markers, or mutations whose locations are already known. For example, if goi-1 segregates independently from unc-104, a reference marker on Chromosome II, we can determine that it is unlinked to unc-13 and therefore NOT on Chromosome II. In contrast, if it fails to segregate independently from unc-32 on Chromosome III, goi-1 is likely linked to unc-32 and therefore also on Chromosome III.
When writing the genotype of two different genes, genes in different linkage groups (chromosomes) are separated by a semicolon (;), while genes in the same linkage group are not. Chromosome numbers are written in Roman numerals after each gene or genes in the same linkage group.
For example, unc-104(e2184)/unc-104(e2184) II ; dpy-17(e164)/dpy-17(+) III refers to an animal that is homozygous for unc-104(e2184) on Chromosome II, and heterozygous for dpy-17 on Chromosome III with one mutant e164 allele and one wild type allele.
unc-32(e189) dpy-17(e164)/unc-32(+) dpy-17(+) refers to an animal that is heterozygous for dpy-17 as above as well as heterozygous for unc-32, carrying one e189 allele and one wild type allele. However, since both unc-32 and dpy-17 are located on Chromosome III, they are written together without the separating semicolon. This notation further indicates that both of the mutant alleles are present together on one homolog (on the left of the slash) while both wild type alleles are present together on the other (on the right of the slash). We refer to this as being in cis, or on the same homolog. The alternative is to have two alleles in trans, or on opposite homologs. Such a genotype would be written as unc-32(e169) dpy-17(+)/unc-32(+) dpy-17(e164). This difference is important, since predictions about offspring genotypes and phenotypes will vary based on the parental and recombinant gametes.
When using reference markers, it is crucial that the phenotype of the reference strain is visibly distinguishable from that of the unknown mutation. In this case, we will use Uncoordinated (Unc) mutants, which you observed in Lab 1. These reference strains are maintained as homozygous hermaphrodites through self-fertilization; there are no males on the plates. Due to their impaired movement, Unc males are unable to mate; therefore, males homozygous for the reference marker alleles cannot be used to set up crosses.
We have the following reference strains available. The Roman numeral in parentheses indicates the chromsome on which the gene is located.
You will also have our unknown mutant hermaphrodites (homozygous for the mutant allele), and N2 (wild-type) males and hermaphrodites.
TO DO:
The F1 progeny produced from the crosses you set up in Lab 2 should contain some animals that are heterozygous for both the reference marker and our gene of interest. However, because the father was heterozygous for our gene of interest, some F1 progeny will have inherited his wild-type allele, and will carry only a mutation in the reference marker gene. Since we cannot distinguish between these animals by their phenotype, we will have to self-fertilize multiple hermaphrodites from each strain.
TO DO:
With your partner, answer the following questions: