Embedded Files
(Please read "scoring" before submission)
Due-date: 2020/10/14 (Wed.) 23:30
Requirement:
Requirement:
Input: 奇數 n (4 的倍數可加分、所有偶數則大加分)
Output: 列、行、對角各數字加總的值皆一樣的魔術矩陣；至少寫出兩種
Bonus:
Bonus:
魔術矩陣的生成有若干方式 (移動方向、起點位置皆可更動)
程式範例 ScreenShots
程式範例 ScreenShots
1) 輸入 7 後，印出 7*7 的 Magic square (以左上角方向填數字)：
2) 輸入偶數，印出要求奇數的訊息：
3) 另一種介面設計，提供四種方向的選擇 (by RadioBotton)
4) 檢測各 row, column, diagonal 的和
5) 利用 StringGrid 呈現方陣
6) Change 1's positions
By students in C++Builder
Bonus
Bonus
Demo Using VS C++ (NOT for C++ Builder; yet, those codes/functions in C are almost the same as those in Builder) "可以不看"
Demo Using VS C++ (NOT for C++ Builder; yet, those codes/functions in C are almost the same as those in Builder) "可以不看"
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