Applied Mathematics

He does some investigation and apply newtons law of cooling,He takes notes of temprature for some times.

Then he applies the equations

If θ(t) is temperature of corpse at time t and Su be the Surrounding temperature.

Then According to Newton’s Law of cooling

dθ(t) dt = −k(θ(t) − Su)

This is a first order linear differential equation.

The solution, under the initial condition θ(0) = θ0, is given by

θ(t) = Su + (θ0 − Su)e −kt

Thus,

θ(t1)−Su θ(t2)−Su = e −k(t1−t2)

⇒ k(t1 − t2) = −ln( θ(t1)−Su θ(t2)−Su)

Putting the given values in the above equations.We get k as

k = (−1/2)(−ln35−28 34−28)

⇒ k = 0.074 4

Supposing initial temperature to be normal body temperature i.e. 37.0 ◦C

(t − t1) = (1/k)(−ln37−28 35−28) =

(t − t1) = −3.38

Converting Decimal into Minutes

t = 18 : 00 − 3 : 22

T = 14 : 38


Thus he can predict that the death has been occurred at 2:38,When he was not in room,he was in lab

Hence He can prove himself innocent by "APPLIED MATHEMATICS"