The first four -illion extensions are from Nirvana Supermind.
We have:
(#15) metillion = [15,4] = 10^(3*10^(3*10^(3*10^45))+3)
from "Metaverse"
(#16) xevillion = [16,4] = 10^(3*10^(3*10^(3*10^48))+3)
from "Xenoverse"
(#17) hypillion = [17,4] = 10^(3*10^(3*10^(3*10^51))+3)
from "Hyperverse"
(#18) omnillion = [18,4] = 10^(3*10^(3*10^(3*10^54))+3)
from "Omniverse"
After that, I will make some name for the 19th tier 4 -illion, called:
(#19) boxillion = [19,4] = 10^(3*10^(3*10^(3*10^57))+3)
from "the Box"
And finally, we are making some base-20 prefixes from 20 to 99 of the tier 4 -illion, using Saibian's nomenclature of the form E100{#,#+1,1,2}n.
We have:
(#20) tweillion = [20,4] = 10^(3*10^(3*10^(3*10^60))+3)
from "tweilasphemorgue"
(#21) kalitweillion = [21,4] = 10^(3*10^(3*10^(3*10^63))+3)
"kalillion + tweillion"
(#22) mejitweillion = [22,4] = 10^(3*10^(3*10^(3*10^66))+3)
"mejillion + tweillion"
(#23) gijitweillion = [23,4] = 10^(3*10^(3*10^(3*10^69))+3)
"gijillion + tweillion"
(#24) astitweillion = [24,4] = 10^(3*10^(3*10^(3*10^72))+3)
"astillion + tweillion"
(#25) lunitweillion = [25,4] = 10^(3*10^(3*10^(3*10^75))+3)
"lunillion + tweillion"
(#26) fermitweillion = [26,4] = 10^(3*10^(3*10^(3*10^78))+3)
"fermillion + tweillion"
(#27) jovitweillion = [27,4] = 10^(3*10^(3*10^(3*10^81))+3)
"jovillion + tweillion"
(#28) solitweillion = [28,4] = 10^(3*10^(3*10^(3*10^84))+3)
"solillion + tweillion"
(#29) betitweillion = [29,4] = 10^(3*10^(3*10^(3*10^87))+3)
"betillion + tweillion"
(#30) glocitweillion = [30,4] = 10^(3*10^(3*10^(3*10^90))+3)
"glocillion + tweillion"
(#31) gaxitweillion = [31,4] = 10^(3*10^(3*10^(3*10^93))+3)
"gaxillion + tweillion"
(#32) supitweillion = [32,4] = 10^(3*10^(3*10^(3*10^96))+3)
"supillion + tweillion"
(#33) versiitweillion = [33,4] = 10^(3*10^(3*10^(3*10^99))+3)
"versillion + tweillion"
(#34) multitweillion = [34,4] = 10^(3*10^(3*10^(3*10^102))+3)
"multillion + tweillion"
(#35) metitweillion = [35,4] = 10^(3*10^(3*10^(3*10^105))+3)
"metillion + tweillion"
(#36) xevitweillion = [36,4] = 10^(3*10^(3*10^(3*10^108))+3)
"xevillion + tweillion"
(#37) omnitweillion = [37,4] = 10^(3*10^(3*10^(3*10^111))+3)
"omnillion + tweillion"
(#38) hypitweillion = [38,4] = 10^(3*10^(3*10^(3*10^114))+3)
"hypillion + tweillion"
(#39) boxitweillion = [39,4] = 10^(3*10^(3*10^(3*10^117))+3)
"boxillion + tweillion"
After some combinations of base-20 n-th-of-tier -illion construction, we will have:
(#40) frielillion = [40,4] = 10^(3*10^(3*10^(3*10^120))+3)
from "frielasphemorgue"
(#50) glocifrielillion = [50,4] = 10^(3*10^(3*10^(3*10^150))+3)
from "glocillion + frielillion"
(#60) fiorilillion = [60,4] = 10^(3*10^(3*10^(3*10^180))+3)
from "fiorilasphemorgue"
(#70) glocifiorilillion = [70,4] = 10^(3*10^(3*10^(3*10^210))+3)
from "glocillion + fiorilillion"
(#80) finnasillion = [80,4] = 10^(3*10^(3*10^(3*10^240))+3)
from "finnasphemorgue"
(#90) glocifinnasillion= [90,4] = 10^(3*10^(3*10^(3*10^270))+3)
from "glocillion + finnasillion"
After the 100th tier 4 -illion, we have:
(#100) hundrelillion = [100,4] = 10^(3*10^(3*10^(3*10^300))+3)
(constructed by me)
(#200) dundrelillion = [200,4] = 10^(3*10^(3*10^(3*10^600))+3)
(constructed by me)
(#300) trundrelillion = [300,4] = 10^(3*10^(3*10^(3*10^900))+3)
(constructed by me)
(#400) tetrundrelillion = [400,4] = 10^(3*10^(3*10^(3*10^1200))+3)
(constructed by me)
(#500) pentundrelillion = [500,4] = 10^(3*10^(3*10^(3*10^1500))+3)
(constructed by me)
(#600) hexundrelillion = [600,4] = 10^(3*10^(3*10^(3*10^1800))+3)
(constructed by me)
(#700) heptundrelillion = [700,4] = 10^(3*10^(3*10^(3*10^2100))+3)
(constructed by me)
(#800) octundrelillion = [800,4] = 10^(3*10^(3*10^(3*10^2400))+3)
(constructed by me)
(#900) nonundrelillion = [900,4] = 10^(3*10^(3*10^(3*10^2700))+3)
(constructed by me)
After tier 4 -illion, we will make some tier 5 -illion, using names from Minecraft.
Here are:
(#1) dirtillion = [1,5] = [1000,4] = 10^(3*10^(3*10^(3*10^3000))+3)
from "dirt"
(#1+) mejidirtillion = [2000,4] = 10^(3*10^(3*10^(3*10^6000))+3)
from "mejillion + dirtillion"
(#1+) gijidirtillion = [3000,4] = 10^(3*10^(3*10^(3*10^9000))+3)
from "gijillion + dirtillion"
(#1+) astidirtillion = [4000,4] = 10^(3*10^(3*10^(3*10^12000))+3)
from "astillion + dirtillion"
(#1+) lunidirtillion = [5000,4] = 10^(3*10^(3*10^(3*10^15000))+3)
from "lunillion + dirtillion"
(#1+) fermidirtillion = [6000,4] = 10^(3*10^(3*10^(3*10^18000))+3)
from "fermillion + dirtillion"
(#1+) jovidirtillion = [7000,4] = 10^(3*10^(3*10^(3*10^21000))+3)
from "jovillion + dirtillion"
(#1+) solidirtillion = [8000,4] = 10^(3*10^(3*10^(3*10^24000))+3)
from "solillion + dirtillion"
(#1+) betidirtillion = [9000,4] = 10^(3*10^(3*10^(3*10^27000))+3)
from "betillion + dirtillion"
(#1+) glocidirtillion = [10000,4] = 10^(3*10^(3*10^(3*10^30000))+3)
from "glocillion + dirtillion"
(#1+) gaxidirtillion = [11000,4] = 10^(3*10^(3*10^(3*10^33000))+3)
from "gaxillion + dirtillion"
(#1+) supidirtillion = [12000,4] = 10^(3*10^(3*10^(3*10^36000))+3)
from "supillion + dirtillion"
(#1+) versidirtillion = [13000,4] = 10^(3*10^(3*10^(3*10^39000))+3)
from "versillion + dirtillion"
(#1+) multidirtillion = [14000,4] = 10^(3*10^(3*10^(3*10^42000))+3)
from "multillion + dirtillion"
(#1+) tweilidirtillion = [20000,4] = 10^(3*10^(3*10^(3*10^60000))+3)
from "tweilillion + dirtillion"
(#1+) frielidirtillion = [40000,4] = 10^(3*10^(3*10^(3*10^120000))+3)
from "frielillion + dirtillion"
(#1+) fiorilidirtillion = [60000,4] = 10^(3*10^(3*10^(3*10^180000))+3)
from "fiorilillion + dirtillion"
(#1+) finnasidirtillion = [80000,4] = 10^(3*10^(3*10^(3*10^240000))+3)
from "finnasillion + dirtillion"
(#1+) hundrelidirtillion = [100000,4] = 10^(3*10^(3*10^(3*10^300000))+3)
from "hundrelillion + dirtillion"
(#2) grassillion = [2,5] = [1000000,4] = 10^(3*10^(3*10^(3*10^3000000))+3)
from "grass"
(#3) stonillion = [3,5] = [1000000000,4] = 10^(3*10^(3*10^(3*10^3000000000))+3)
from "stone"
(#4) sandillion = [4,5] = [1[3],4] = 10^(3*10^(3*10^(3*10^(3*10^12)))+3)
from "sand"
(#5) gravillion = [5,5] = [1[4],4] = 10^(3*10^(3*10^(3*10^(3*10^15)))+3)
from "gravel"
(#6) cobbillion = [6,5] = [1[5],4] = 10^(3*10^(3*10^(3*10^(3*10^18)))+3)
from "cobblestone"
(#7) granitillion = [7,5] = [1[6],4] = 10^(3*10^(3*10^(3*10^(3*10^21)))+3)
from "granite"
(#8) diorillion = [8,5] = [1[7],4] = 10^(3*10^(3*10^(3*10^(3*10^24)))+3)
from "diorite"
(#9) andesillion = [9,5] = [1[8],4] = 10^(3*10^(3*10^(3*10^(3*10^27)))+3)
from "andesite"
(#10) coalillion = [10,5] = [1[9],4] = 10^(3*10^(3*10^(3*10^(3*10^30)))+3)
from "coal"
(#11) cuprillion = [11,5] = 10^(3*10^(3*10^(3*10^(3*10^33)))+3)
from "copper"
(#12) ironillion = [12,5] = 10^(3*10^(3*10^(3*10^(3*10^36)))+3)
from "iron"
(#13) silvillion = [13,5] = 10^(3*10^(3*10^(3*10^(3*10^39)))+3)
from "silver" (in Minecraft it don't have silver as of 1.18)
(#14) goldillion = [14,5] = 10^(3*10^(3*10^(3*10^(3*10^42)))+3)
from "gold"
(#15) platillion = [15,5] = 10^(3*10^(3*10^(3*10^(3*10^45)))+3)
from "platinum" (again, yet Minecraft don't have this mineral in 1.18)
(#16) redillion = [16,5] = 10^(3*10^(3*10^(3*10^(3*10^48)))+3)
from "redstone"
(#17) lapillion = [17,5] = 10^(3*10^(3*10^(3*10^(3*10^51)))+3)
from "lapis lazuli"
(#18) diamillion = [18,5] = 10^(3*10^(3*10^(3*10^(3*10^54)))+3)
from "diamond"
(#19) emerillion = [19,5] = 10^(3*10^(3*10^(3*10^(3*10^57)))+3)
from "emerald"
(#20) amethillion = [20,5] = 10^(3*10^(3*10^(3*10^(3*10^60)))+3)
from "amethyst"
(#40) topazillion = [40,5] = 10^(3*10^(3*10^(3*10^(3*10^120)))+3)
from "topaz" (not in Minecraft as of 1.18)
(#60) sapphillion = [60,5] = 10^(3*10^(3*10^(3*10^(3*10^180)))+3)
from "sapphire" (not in Minecraft as of 1.18)
(#80) rubillion = [80,5] = 10^(3*10^(3*10^(3*10^(3*10^240)))+3)
from "ruby" (not in Minecraft as of 1.18)
(#100) netherillion = [100,5] = 10^(3*10^(3*10^(3*10^(3*10^300)))+3)
from "netherrack"
(#200) obsidillion = [200,5] = 10^(3*10^(3*10^(3*10^(3*10^600)))+3)
from "obsidian"
(#300) magmillion = [300,5] = 10^(3*10^(3*10^(3*10^(3*10^900)))+3)
from "magma"
(#400) basillion = [400,5] = 10^(3*10^(3*10^(3*10^(3*10^1200)))+3)
from "basalt"
(#500) blackillion = [500,5] = 10^(3*10^(3*10^(3*10^(3*10^1500)))+3)
from "blackstone"
(#600) glowillion = [600,5] = 10^(3*10^(3*10^(3*10^(3*10^1800)))+3)
from "glowstone"
(#700) quartzillion = [700,5] = 10^(3*10^(3*10^(3*10^(3*10^2100)))+3)
from "nether quartz"
(#800) soulillion = [800,5] = 10^(3*10^(3*10^(3*10^(3*10^2400)))+3)
from "soul" (such as "soul sand", "soul soil", etc.)
(#900) netheritillion = [900,5] = 10^(3*10^(3*10^(3*10^(3*10^2700)))+3)
from "netherite"
You can make intermediate tier 5 -illions by just concatenating the prefix ending in i-. For example:
(#999) emerirubinetheritillion = [999,5] = 10^(3*10^(3*10^(3*10^(3*10^2997)))+3)
from "emerillion + rubillion + netheritillion"
You are adopt some names from Minecraft up to tier 6.
(#1) endillion = [1,6] = [1000,5] = 10^(3*10^(3*10^(3*10^(3*10^3000)))+3)
from "end stone"
(#2) prismarillion = [2,6] = [1000000,5] = 10^(3*10^(3*10^(3*10^(3*10^3000000)))+3)
from "prismarine"
(#3) purpurillion = [3,6] = [1000000000,5] = 10^(3*10^(3*10^(3*10^(3*10^3000000000)))+3)
from "purpur"
(#4) honillion = [4,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^12))))+3)
from "honey"
(#5) glassillion = [5,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^15))))+3)
from "glass"
(#6) clayillion = [6,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^18))))+3)
from "clay"
(#7) brickillion = [7,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^21))))+3)
from "brick"
(#8) concretillion = [8,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^24))))+3)
from "concrete"
(#9) bookillion = [9,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^27))))+3)
from "bookshelf"
From #10 to #90, I will use the names from the Nether Update in 1.16:
(#10) crimsillion = [10,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^30))))+3)
from "crimson"
(#20) warpillion = [20,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^60))))+3)
from "warped"
(#30) cryillion = [30,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^90))))+3)
from "crying obsidian"
(#40) gildillion = [40,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^120))))+3)
from "gilded blackstone"
(#50) lodillion = [50,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^150))))+3)
from "lodestone"
(#60) anchorillion = [60,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^180))))+3)
from "respawn anchor"
(#70) shroomillion = [70,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^210))))+3)
from "shroomlight"
(#80) chainillion = [80,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^240))))+3)
from "chain"
(#90) ancienillion = [90,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^270))))+3)
from "ancient debris"
From #100 to #900, I will use the miscellaneous Minecraft items as the name:
(#100) stickillion = [100,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^300))))+3)
from "stick"
(#200) bonillion = [200,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^600))))+3)
from "bone"
(#300) flintillion = [300,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^900))))+3)
from "flint"
(#400) enderillion = [400,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^1200))))+3)
from "ender pearl"
(#500) blazillion = [500,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^1500))))+3)
from "blaze" (item)
(#600) nautillion = [600,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^1800))))+3)
from "nautilus shell"
(#700) dragonillion = [700,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^2100))))+3)
from "dragon's breath"
(#800) witherillion = [800,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^2400))))+3)
from "wither" (as an item "nether star")
(#900) seaheartillion = [900,6] = 10^(3*10^(3*10^(3*10^(3*10^(3*10^2700))))+3)
from "heart of the sea"
Hang on… How I start at metillion? Guess what, the naming gaps were already filled. I was going meta for nonstandard illions whatsoever.
But, one ubiquitous issue. If I take met and put the first letter off, it would result the same as I do to bet. They are splitted into 2 identical "et."
(taking the first letter out: bet -> et, met -> et), but why it's bet -> -eet, and met = -ett!
But why, for other tiers, we should have:
(Tier 1 multiplicative: deci- + metillion = decimetillion)
(Tier 2 multiplicative: veci- + metillion = vecimetillion)
(Tier 1 additive: metillion + million = metimillion)
(Tier 2 additive: metillion + micrillion = metimicrillion)
(Tier 3 additive: metillion + dakillion = metidakillion)
For extended illions from tweillion to seaheartillion, I will just concatenate the names using the vowel "i".
We can eventually construct a very complex -illion name, such as
(#666+ of tier 4) exotexakectejitweihexundrelillion = [666*10^666,3] = 10^(3*10^(3*10^(1.998*10^2001))+3)
(#999+ of tier 5) boxifinnasinonundreliemerirubinetheritillion = [999*10^999,4] = 10^(3*10^(3*10^(3*10^(2.997*10^3000)))+3)
(#999+ of tier 6) emerirubinetheritibookiancieniseaheartillion = [999*10^999,5] = 10^(3*10^(3*10^(3*10^(3*10^(2.997*10^3000))))+3)