// Input: A list of elements

procedure FindLength(list)

    length ← 0

    for i ← 0 to length of list - 1 do

        length ← length + 1

    end for

    print length

end procedure

def find_length(lst):

    length = len(lst)

    print(length)

# Example usage

find_length([1, 2, 3, 4, 5])

import java.util.Scanner;

import java.util.List;

import java.util.ArrayList;

public class ListLengthFinder {

    public static void findLength(List<Integer> list) {

        System.out.println(list.size());

    }

    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);

        List<Integer> list = new ArrayList<>();

        System.out.println("Enter the number of elements: ");

        int n = scanner.nextInt();

        System.out.println("Enter the elements: ");

        for (int i = 0; i < n; i++) {

            list.add(scanner.nextInt());

        }

        findLength(list);

    }

}

#include <iostream>

#include <vector>

using namespace std;

void findLength(const vector<int>& list) {

    cout << list.size() << endl;

}

int main() {

    int n, element;

    vector<int> list;

    cout << "Enter the number of elements: ";

    cin >> n;

    cout << "Enter the elements: ";

    for (int i = 0; i < n; i++) {

        cin >> element;

        list.push_back(element);

    }

    findLength(list);

    return 0;

}