Pattern printing

Type 1

Example 1

Input:

7

Output:

*1

21*

*123

4321*

*12345

654321*

*1234567

Example 2

Input:

2

Output:

*1

21*

#include<stdio.h>

int main() {

    int n;

    scanf("%d",&n);

    for(int i=1;i<=n;i++)

    {   int a=i;

        for(int j=1;j<=i;j++)

           (i%2==1&&j==1)&&(printf("*"));

            (i%2==1)&&(printf("%d",j));

            (i%2==0)&&(printf("%d",a--));

            (i%2==0&&j==i)&&(printf("*"));

        printf("\n");

#include<stdio.h>

int main() {

   char string[1001];

   int len;

   scanf("%s%n",string,&len);

   int start=0,end=len-1;

    for(int i=0;i<len;i++)

        for(int j=0;j<len;j++)

            if(j==start||j==end)

                printf("%c",string[j]);

            else

                printf(" ");

        start++;

        end--;

        printf("\n");

Example:

Input

4 5

80 50 45 86 20

48 57 10 44 30

22 47 58 44 27

74 36 84 40 99

Output:

80 50 45 86 44 44 40

48 57 10 58 84

22 47 36

74

#include<stdio.h>

#include <stdlib.h>

int main()

int n;

scanf("%d",&n);

int mat[n][n];

for(int row=1;row<=n;row++)

    for(int col=1;col<=n;col++)

        scanf("%d ",&mat[row][col]);

int ctr=(n*2)-1,len=n;

for(int i=1;i<=n;i++)

{   int a=i,b=1,k=0;

    for(int j=1;j<=ctr;j++)

        printf("%d ",mat[a][b]);

        if(j%len==0)

            k=1;

        if(k==0)

            b++;

        else

            a++;

    ctr=ctr-2;

    len--;

    printf("\n");