I thought it was 500k, too, which is a little weird, since they don't tell you this in any of the included literature or online, and it's... sorta important, while they average joe wouldn't know the different and would just think the pickup sucked.
For what it's worth, I didn't bother changing out the 250k pot in my Strat when I installed my own SD Lil'59 in the bridge, so a 250k will work just fine. A 500k pot might sound a tad brighter... so truthfully, either will work.
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I have a dimarzio dp218 in my 66 mustang,i was running it through 500k pots with a .05uF cap but about half hour ago i swapped for the original 250kpots and a .05uF cap,sounds a little warmer,highs are less pronounced and overall i like it better.
The two most common pot values used in guitar circuits are 250k and 500k. 250k pots are commonly used in single coil pickup guitars ie. in a Strat or Tele, whilst 500k pots are generally used with humbucker pickups. There are also other notable values, including 300k and 1meg pots.
The value simply refers to the resistance of the pot. Pots are essentially variable resistors. Higher value pots will give the guitar a brighter tone and the lower the pot value, the warmer the tone will sound. The higher the value of the pot, the less the load on the pickup which prevents the treble frequencies from bleeding out. Put simply, the higher the pot value, the more treble you will hear.
This is why a Les Paul will generally use 500k pots as they are better at retaining the high end frequencies for a slightly brighter tone, whilst Stratocasters tend to use 250k pots to add warmth and depth to the tone by reducing the high frequencies. This is to counteract the naturally high sounding single coil pickups. Humbucker pickups are well known for their deeper, mellower tones with less treble than single coils so 500k pots are used to offer a little more brightness and reduce the treble loss.
The law of Kirchhoff states that a voltage has to be equally distributed over all resistors in a circuit, relative to the resistors. That law is of great help to understand what a pot does. Suppose that a pickup produces 100 volts and the potmeter is 100 ohms. When the pot is fully open, the first resistor (R1) is 100 ohms and the second resistor (R2) is 0 ohms. The entire 100 volts goes over the first resistor, because the law of Ohm comes into play. That law gives the relation between voltage, current and resistance: U=IR. The U is voltage, I is current and R is the combined value of R1 and R2 (so, R1+R2=R). In other words, if R2 is 0, the whole signal has to go to R1, because you cannot devide by zero. That goes the other way around, too: If R1=0, R2 has to be 100, so the signal has to go all the way on R2, and since R2 is connected to earth, we cut out our signal.
The entire filter also has a resonance peak, though. This means that the way the filter filters differs with its components. In practice you can say that a 500k pot and a 470 PuF capacitor will roll off different high frequencies (and other frequencies, too!) than a 250k pot and a 220 PuF capacitor. Playing around with this will give you different results and might lead to a tone you like.
The resistance of the potentiometer that goes over the second order filter is actually the most important bit. It changes the amplitude of the cut off frequency. The lower it is, the harder it attenuates the higher frequencies because of the relative impact it has on the impedance of the second order filter (i.e.: the pickup). The higher it is, the less impact it has, the less it can shift the cut off frequency, and the less highs you lose.
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