Project 1: Intersection of Sloped Lines
In the example above, the red line has slope -1 and y-intercept 2. The blue line has slope 1 and y-intercept -4.
The equation of the first line is: y = -x + 2. The equation of the second line is: y = x - 4
Using the substitution method, we can let -x + 2 = x - 4.
Solving this algebraically yields: -2x = -6, which yields x = 3.
If we substitute x = 3 into either equation, we obtain y = -1.
Therefore, the solution to the system of equation is (3, -1), which is the point where the lines intersect.
Example 2:
y = -2x + 7
y = 3x - 3
Substitution: -2x + 7 = 3x - 3
Solving: -5x = -10
x = 2
Substituting: y = -2(2) + 7 = 3
Intersection point occurs at (2, 3).
Project 1: Variables 'm1', 'b1', 'm2', 'b2' are initialized.
Task: Assign the variables appropriately so that 'x' and 'y' represent the x and y values for the intersection point.
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