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More notes on (Example 10 d):
(option 1) Apply ln to both sides,
ln ((ln n)^(ln n))= ln n (ln(ln n)) > 2 ln n = ln (n^2),
so, (ln n)^(ln n) > n^2
and 1/[ (ln n)^(ln n) ] < 1/(n^2) = b_n
(option 2) Observe that
(ln n )^(ln n) = n^(ln(ln n))
(this equality can be obtained by Applying ln to both sides, we have
ln ((ln n)^(ln n))= ln (n^(ln(ln n)))
and ln n (ln(ln n)) = ln(ln n) (ln n) )
Since n^(ln(ln n)) > n^2
we have (ln n )^(ln n) = n^(ln(ln n)) > n^2
hence 1/[ (ln n)^(ln n) ] < 1/(n^2) = b_n