Puffed Cheese

How we got our answer

Our procedure to get this answer:   

-We First measured out the mass of two different kinds of cheetos: cheeto puffs and the crunchy cheetos. The mass of the cheeto puff was 1.723 grams and the mass of the small cheeto puff was 0.666 grams. 

-Second we had to measure out 150 milliliters of water and pour it into a flask.

-Third we burned the cheeto puff under the flask of water and measure the temperature change of the water from it's beginning to it's end.  It first measured 20.7 degrees celsius, then it changed to 35.2 degrees celsius.  We then figured out the change in temperature by subtracting the heat before burning the cheeto puff to the heat after burning the cheeto puff so the equation was        35.2 - 20.7 and we figured out that the temperature change was 14.5 degrees Celsius.   

- Fourth we measured the mass of the cheeto puff after it was burned and we got 0.727 grams.  We then subtracted the mass of the burned cheeto from the mass of the cheeto before it was burned and found out that the cheeto lost .996 grams from its mass.

- Fifth we did the same thing with a crunchy cheeto burning the crunchy cheeto under a 150 ml flask of water.  The original temperature of the water was 21.3 degrees Celsius and after the cheeto was burned the temperature of the water was 25.3 degrees Celsius we figured out the change in temperature by subtracting the first measurement from the second measurement so the equation was 25.3 - 21.3 and the answer was that the water changed temperature by 4 degrees celsius.

-Next we measured the mass of the cheeto after it was burned using a balance and we got 0.372 grams.  We got this by subtracting the mass of the cheeto after it was burned from the mass of the cheeto before it was burned and we got figured out that .294 grams of the cheeto was burned.  We used the equation 0.666-0.372 and got 294 grams.

-Now that we had all of our measurements complete we next needed  to figure out how many joules that the cheeto produced from burning.  We figured this out by using the equation q = mc ΔT .  Q represents the amount of energy gained or lost in a system.  M represents the mass of the sample. C represents the specific heat.  ΔT represents the change in temperature.

-  So the equation we did for the cheeto puff was:      q= (150)(4.18)(14.5)  and we got q= 9091.5 joules but with sig figs it's 9090 joules.  The 150 represents the mass of the water in grams, the 4.18 represents the heat capacity of liquid water, and the 14.5 represents the change in temperature of the water before the cheeto was burned versus after the cheeto was burned.  

-We did this same equation with the crunchy cheetos: q= (150) (4.18) (4) and we got q= 2510 joules.  The 150 represents the mass of the water in grams, the 4.18 represents the heat capacity of liquid water, and the 4 represents the change in temperature of the water before the cheeto was burned versus after the cheeto was burned.  

- We then converted the energy added into the water from joules to calories with the conversion of 4.184 joules to 1 calorie.  The cheeto puffs energy was 2170 calories of heat, and the crunchy cheetos energy was 600 calories of heat.  

-We then converted the calories to Kcals to get that the cheeto puff gave off 2.17 Kcals of heat and the crunchy cheeto gave off 0.6 Kcals of heat.

-We then divided the Kcals by the mass of the cheeto to figure out the Kcals per grams of the cheeto puff consumed.  We took the Kcal of the cheese curl and got 2.17 Kcal of heat and divided this by 1 because 1 gram of the cheeto was burned.  We then divided 2.17/1 and we got that there are 2.17 Kcals per gram of the cheeto puff consumed. 

-We then did this same equation with the crunchy cheeto the K cal of the cheeto and got 0.6 Kcal and we then divided this by .294 because that was how many grams of the cheeto was burned and we got the equation 0.6/.294 and we got 2.04 Kcals per gram of cheeto consumed.

-We can calculate the percent error of our calculations of doing this same equation with the nutrition facts on the label, of 90 Kcalories from fat per 28 grams of cheeto and we did the equation : 90/28 and we got 3.2 Kcalories of fat per gram.  This was for the crunchy cheetos.

-For the puffy cheetos we can do this same equation of doing this same equation with the nutrition facts on the label it is basically the same thing as the crunchy cheetos where there is 90 Kcals from fat per 28 grams and we then did this equation of 90/28 and got 3.2 Kcalories of fat per gram.  

-Finally using this we can figure out the percent error of this equation for the crunchy cheetos the Kcalories of fat per gram is 3.2 and our result of 2.04.  We then can do this by subtracting 2.04-3.2/3.2 times 100 and we got 36% error.

-We as well can find the percent error of cheeto puffs by taking the fat per gram of the puffy cheetos based off of the nutrition facts which is 3.2 and from our result from our experiment getting 2.17-3.2/3.2 times 100 and we got a 32% error.

-There are many potential reasons we got this error: first we may have measured the mass incorrectly at the beginning or maybe we calculated the mass change wrong.  We could've made other mistakes through making errors when measuring our water like maybe we spilled some of the water out of the system.  We may have also of done some of our calculations wrong.

Video of us burning the cheeto Video_1.mov