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Quantum Field Fractal Polarization Math Constants
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Given L=∈1⅄(1⅄Qn2/2⅄Qn1)cn
∈1⅄2Qn1 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn2/2⅄1Qn1)=(1.^6/0.^6)=2.^6 depending of cn variable factor c1
then
Ln1=∈1⅄2Qn1 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn2/2⅄1Qn1)=(1.^6/0.^6)=2.^6 or 2.666 and so on...
Ln2=∈1⅄2Qn2 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn3/2⅄1Qn2)=(1.4/0.6)=2.^3 or 2.333 and so on...
Ln3=∈1⅄2Qn3 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn4/2⅄1Qn3)=(1.^571428/0.^714285)=2.2^000014 or 2.2000014000014000014 and so on...
Ln4=∈1⅄2Qn4 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn5/2⅄1Qn4)=(1.^18/0.^63)=1.^873015 or 1.873015873015873015 and so on...
Ln5=∈1⅄2Qn5 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn6/2⅄1Qn5)=(1.^307692/0.^846153)=1.^545455727273909092090910272728454546636364818183000001181819363637 or 1.^545455727273909092090910272728454546636364818183000001181819363637545455727273909092090910272728454546636364818183000001181819363637545455727273909092090910272728454546636364818183000001181819363637 and so on...
Ln6=∈1⅄2Qn6 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn7/2⅄1Qn6)=(1.^1176470588235294/0.^7647058823529411)=1.^461538461538461669230769230769243846153846153847 or 1.461538461538461669230769230769243846153846153847461538461538461669230769230769243846153846153847461538461538461669230769230769243846153846153847 and so on...
Ln7=∈1⅄2Qn7 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn8/2⅄1Qn7)=(1.^210526315789473684/0.^894736842105263157)=1.^352941176470588236411764705882352942294117647058823530529411764705882354058823529411764707000000000000000001117647058823529412882352941176470589 or 1.352941176470588236411764705882352942294117647058823530529411764705882354058823529411764707000000000000000001117647058823529412882352941176470589352941176470588236411764705882352942294117647058823530529411764705882354058823529411764707000000000000000001117647058823529412882352941176470589352941176470588236411764705882352942294117647058823530529411764705882354058823529411764707000000000000000001117647058823529412882352941176470589 and so on...
Variable Factor 1⅄2Qnc1 will differ variants of ∈1⅄2Qn given a factor 1⅄1Qnc2 factor 2⅄1Qnc2 and so on . . .