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Quantum Field Fractal Polarization Math Constants
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ᐱ Y φ Θ P Q Ψ
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Given K=∈2⅄(1⅄Qn1/2⅄Qn2)cn
∈2⅄2Qn1 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn1/2⅄1Qn2)=(1.5/0.6) depending of cn variable factor
then
Kn1=∈2⅄2Qn1 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn1/2⅄1Qn2)=(1.5/0.6)=2.5
Kn2=∈2⅄2Qn2 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn2/2⅄1Qn3)=(1.^6/0.^714285)=^2.24000 or 2.24000224000 and so on...
Kn3=∈2⅄2Qn3 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn3/2⅄1Qn4)=(1.4/0.^63)=^2.22 or 2.222222 and so on...
Kn4=∈2⅄2Qn4 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn4/2⅄1Qn5)=(1.^571428/0.^846153)=1.^857144038962220780402598584416766234948053129871311689493507675325 or 1.857144038962220780402598584416766234948053129871311689493507675325857144038962220780402598584416766234948053129871311689493507675325 and so on...
Kn5=∈2⅄2Qn5 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn5/2⅄1Qn6)=(1.^18/0.^7647058823529411)=^1.54307692307692323123076923076924620000000000000 or 1.54307692307692323123076923076924620000000000000154307692307692323123076923076924620000000000000 and so on...
Kn6=∈2⅄2Qn6 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn6/2⅄1Qn7)=(1.^307692/0.^894736842105263157)=^1.46153811764705882499094988235294117793212635294117647204977341176470588381447929411764706028506752941176470734389105882352941322624400000000000 or 1.46153811764705882499094988235294117793212635294117647204977341176470588381447929411764706028506752941176470734389105882352941322624400000000000146153811764705882499094988235294117793212635294117647204977341176470588381447929411764706028506752941176470734389105882352941322624400000000000 and so on...
Kn7=∈2⅄2Qn7 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn7/2⅄1Qn8)=(1.^1176470588235294/0.^8260869565217391304347)=^1.35294117647058822105276687306501547987473685563467492260061905263293188854489164085263171424148606811145368422405572755417956642105398452012383900927368434582043343653250631580300309597523219800000 or 1.35294117647058822105276687306501547987473685563467492260061905263293188854489164085263171424148606811145368422405572755417956642105398452012383900927368434582043343653250631580300309597523219800000135294117647058822105276687306501547987473685563467492260061905263293188854489164085263171424148606811145368422405572755417956642105398452012383900927368434582043343653250631580300309597523219800000 and so on....
Variable Factor 2⅄2Qnc1 will differ variants of ∈1⅄1Qn and ∈2⅄1Qn given a factor 1⅄1Qnc2 factor 2⅄1Qnc2 and so on . . .