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Given K=∈2⅄(1⅄Qn1/2⅄Qn2)cn
∈2⅄2Qn1 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn1/2⅄1Qn2)=(1.5/0.6) depending of cn variable factor
then
Kn1=∈2⅄2Qn1 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn1/2⅄1Qn2)=(1.5/0.6)
Kn2=∈2⅄2Qn2 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn2/2⅄1Qn3)=(1.^6/0.^714285)
Kn3=∈2⅄2Qn3 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn3/2⅄1Qn4)=(1.4/0.^63)
Kn4=∈2⅄2Qn4 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn4/2⅄1Qn5)=(1.^571428/0.^846153)
Kn5=∈2⅄2Qn5 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn5/2⅄1Qn6)=(1.^18/0.^7647058823529411)
Kn6=∈2⅄2Qn6 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn6/2⅄1Qn7)=(1.^307692/0.^894736842105263157)
Kn7=∈2⅄2Qn7 of ∈1⅄1Qn and ∈2⅄1Qn variables is (1⅄1Qn7/2⅄1Qn8)=(1.^1176470588235294/0.^8260869565217391304347)
Variable Factor 2⅄2Qnc1 will differ variants of ∈1⅄1Qn and ∈2⅄1Qn given a factor 1⅄1Qnc2 factor 2⅄1Qnc2 and so on . . .
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