counting lattice points on a line median length cube path counting counting points of intersection for circle
red cards and black cards 2010 Nat TA8
https://artofproblemsolving.com/community/c2113h1028356s3_2010_mathcounts_national_target_problem_8
https://en.wikipedia.org/wiki/List_of_small_polyhedra_by_vertex_count
rectangle interior point integer distance - 2019 national target 2
10 coin flips - 2019 national target 4
in how many sequences of ten coin flips does the coin never land heads up at least five consecutive times?
2019 national target 8 solution-
trinomial coefficient trig identities
need to know
sqrt5=2.236, tan15=2-sqrt3, (a+b)^3
bayes theorem/conditional probability
circle angle jumping technique
cut the crap-
triangle counting, similar to sum of n^2: floor of n(n+2)(2n+1)/8
sum of n: n(n+1)/2
sum of squares: n(n+1)(2n+1)/6
sum of cubes: n^2(n+1)^2/4
establish x-y coordinate systems and use line equations to solve problems, especially for right triangles,
rectangles, any shape with 90-degree angles
2011-2016 national sprint/target solutions
2019 sprint 30: https://youtu.be/v-mfAS2IkM8
https://youtu.be/NGo8AM3TCKE 2018 sprint 28
https://youtu.be/0NFsL4z68Ww 2017 t8
https://youtu.be/_MkGAYonnCc 2016 s29
1992 target 2 time of seconds should be decimal not fraction; 4 geometric series need to be careful; 6/8 right
1993 target 3 6 wrong; 6/8 right; 3 worm grow x+2 / 2 = 20, x=38; 6 integer parts of fraction is just integer result from division!
1994 target wrong 2 ( teacher sharing cost $78, two no money, others each add $1.30), 4, 5,6,8; 8 is AM-GM inequality; 6 exterior angle; 5 list out first and last 5 terms, others cancel out; 4 k, n, m int, 2 3 7;
1995 target wrong 5 7; inch took as feet; rectangle counting missing 1; use combination for counting, not baby counting!
1996 target 3 4 5; 7/10< 5/7<8/11, 5/7 goes in between!! 5/8 right; sprint wrong 3 6 8 10 13 15 18 20 22;
right 21 24 23 1/(1+sqrt2) = sqrt2-1; 25-30 not done; fixed all of it
1997 target 3 5 7 8 wrong; inch not feet; hollow cylinder has inside as area also! 0 and 1 are both power of 4 numbers, don't miss 0; sprint wrong 4, 8, 9, 12, 13, 14, 16, 18, 21; 25-30 not done; 27 got x-y coordinates but asking sum of them 9+7=16!
1998 sprint 2 11 13 21 wrong; 26/30 right; target 8/8 right
1999 sprint wrong 1 9 10 16 21 22 24-30; 23 right; target wrong 2 (8.5 month goes to September! not august) 8 semicircle counted only half of chord, should be 2x;
2000 national target wrong 4 5 8; 4 is 9 dots counting isoceles; 5 digits sieving; 9 marble blue and green easy; sprint worked backwards 1 ok; 2-11 not done; wrong 16, 17 19 23 24 30; total 14 right. hosting timed team work
2001 target 2 3 wrong; total 6 right; sprint 1-10 right; wrong 11 12 14 24 25 27 29 30; right 26 28; 23 answer -14 looks like -19!!
2002 national sprint 14 16 23 24 25 wrong; 28-29 not done; 30 right; target 8 wrong; 1-7 right
2002 target 8 plot x^(a/x) for any constant integer a, solution is e=2.718, so maximize number of 3's in!
2003 national sprint wrong 2 4 13 up to 23; 20 right ; 21 is 1/4 not 1/9! finished 24 -30; wrong 27 4 vs 8 digits; 29 horseshoe shape with 3 lines cut region - crooked get 10; 30 - don't count >6 digits! https://math.stackexchange.com/questions/758466/probability-of-number-formed-from-dice-rolls-being-multiple-of-8
2003 national target 3 4 wrong; 7 8 right
2004 national sprint 12 17 18 wrong; 21 24 25 right; total 20 right; 22 region is a triangle plus a circle segment - 2+135/360*pi*16=2+6*pi; 23 8!=40320=32*35*36, just factor it out; 26. 5^3*3^3*5^4*2^2*1, a=50, b=15,c=1 answer is 750-1; target 2 4 8 wrong; TA8 doesn't have a simple way, need to loop through all the 2x3^n numbers 2 6 18 54 162 486 1458, subtract from 2004, and mod 7; TA 4 convert from real numbers to shapes on x-y coordinate system, probability to geometry, connection!
2004 sprint 12 17 18 ; 22 23 not done; 24 25 right; 26-30 not done
2005 sprint total 18 right; wrong 8, 12 17 18 23 25 26 30 gecko; target wrong 3 4 6 7; right 8; hosting team timed work
2006 sprint wrong 4 13 14 15 16 17 22-30 not done; target 6 8 wrong;
2007 sprint wrong 5 7 10 16 19 21; 23-30 not done; 22 right; total 16 right; target 1 6 8 wrong
2008 target national 3 5 6 8 wrong; 4 crossed out; sprint wrong 17 18 21 22 23 25-30 not done; 24 right
2009 target 3 5 7 wrong; sprint wrong 6 8 14 15 18 21 25-26 not done but looked up solutions
2010 target 6 8 wrong 1-7 right; sprint 3 crossed out, 7 9 12 13 16 18 23 wrong; 19 20 right
2011 sprint 15 16 wrong, 21 crossed out; did up to 18 in school, figured out remaining later to #30; target 6 8 not done; 5 7 1-4 all right! 5 is semicircle one
2012 national sprint wrong 1 6 11 20-24 not done 25 right 26-30 not done; target 7 8 not done; 1-6 right?
2013 national target - 3 4 5 6 8 wrong; sprint 15 16 22 wrong; 24 right; 23 25-30 not done; need review
2014 targe 4 6 7 8 wrong; sprint 2 10 13 wrong; only did 1-13
2015 target 3 4 6 8 wrong; 2015 sprint explained 25-30; 2nd time doing it 26 wrong even though it was right before; 29-30 not done? sprint 1-14 16 18 20-23 right; 15 17 19 24wrong; 25-30 not done; team did 7 binary tree combination 14C7x6C3^2x2C1^4; 10 did trichotomy with 3 weather types
2016 national sprint did only one 27 right; 2016 national target 2 should know
2017 national sprint, target and team round all done - not sure how many correct
2018 national target 2 3 7 8 wrong; total 4 right; sprint hard only did 1-15 in time; 26-30 not figured out
2018 sprint wrong 9 10 12-15; right 11 1-8; team has solutions from yongcheng, didn't do
2019 national sprint 1-12 right; 13 14 15 16 18 wrong; 17 19 20 right; 21-30 not done; target wrong 2 4 6 8; total 4 correct; team did 5 magic square
self solutions below -
2010 national team round -
1. 4 multiples 15, 5 multiples 12, with 3 overlapping: 24
4*3's 12 24 36 48 60
5*6's 30
24 take out 6 is 18;
2. linear equations - sandra knows
3. mean median mode and range of 8 intergers are each 10, what is larget integer?
https://artofproblemsolving.com/wiki/index.php/2002_AMC_12A_Problems/Problem_15
7 7 9 10 10 10 10 17
4. linear equations - sandra knows
5. recursively solve down on 5 to 0
6. cylinder volume - sandra knows
7. total is 3^6; 6 x 9 - 1; 4x9, 1x10,8 - 30; 2x9, 2x8, 10 - 90; 3x8,10 - 20; add up to
141/3^6 = 47/243
8. chicken nugget theorem shift right to 1; 7*11-7-11+1
9. use similar shape ratio 1/9 for small segments - on stack exchange math!
10. simple geometry with middle point coordinates - easy
http://mathteamnyc.weebly.com/mathcounts.html has most past years mathcounts
https://www.sycamoreschool.org/academics/academic-teams
http://www.aquatutoring.org/miscmath.php chicago
https://mathprize.atfoundation.org/resources/past-tests/2019/mathprize2019problems.pdf
math for girls
https://ivyleaguecenter.org/2017/09/30/35-sets-of-previous-official-amc-10-tests-with-answer-keys/
https://ivyleaguecenter.files.wordpress.com/2016/02/2016_amc10b.pdf washington DC
AMC 10 https://www.cut-the-knot.org/proofs/ptolemy.shtml
2016 national sprint
4. 7/2>14/5>1/10
biggest is (7/2+14/5)/(1/10) smallest is 1/10 / (7/2+14/5)!
10. biggest square number <43 is 6^2, so A=6
11. look for 1/a near 1/3, a=3, b=4, c=6
12. pick any point first, then 3 subcases:
case 1) picking 2 next points, then 2 opposite points: 2/5 * 2/4 = 1/5;
case 2) picking 2 longer points, then each has 2 points of choice: 2/5 * 2/4 = 1/5;
case 3) picking 1 opposite point, any third point will for a right triangle: 1/5
sums up to 3/5 answer
19 https://artofproblemsolving.com/wiki/index.php/1985_AHSME_Problems/Problem_14
24 use logrithm, y+y^2=3/2, solve for y positive, -1+sqrt7/2
z^2=(1+2y)^2=7
20 can only be 785 + 785 + 785 = 02355, THREE sums to 15
21 4/5 x 2/3 = 8/15
22 b=2+3a, solve 3 a^2 - 2a -225=0, a=9, b=29 answer 38
27. total number ways of moves are 4^4=256
face 1 to 2 as one example (there are 4 of them): to go back to face 1, there are total 12 ways:
face 3 first: 12341, 12351, 12361, 12321 - 4 of them
face1 next: 12121, 12151, 12161, 12151 - 4 of them
face 5 next: 12521, 12541 - 2 of them
face 6 next: 12621, 12641 - 2 of them
so each of the 4 face 1 goes to, there are 12 ways to go back to face 1, that's 12*4=48 ways
48/256=3/16 answer
markov chain - https://math.stackexchange.com/questions/2542476/random-walk-over-a-cubeprobability-of-returning-back?rq=1
28 programming - n28.cc
programming seal meeting problem? how to program combinatorics? and probability?
29
not understanding it first - why? regular octagon has different squares inscribed????
https://web2.0calc.com/questions/regular-octagon-abcdefgh-has-a-side-length-of-2-cm
https://artofproblemsolving.com/wiki/index.php/2003_AMC_10B_Problems/Problem_23
30. easy with pythagorean theorem, drop altitude to BC
x/y=9/5
h^2+(9+5/2)^2 =x^2
h^2+2.5^2=y^2
solve y=15/2, x=27/2, perimeter =27+23=50 answer
2016 national team
6. 11*7*19-17*7*12 = 35
7. let small side to be x, 1+x+sqrt(x^2+1)=6, solve x=2.4, area = 36-2.4*2=31.2 answer
8. 3 30 300 12 and 75! sums to 420 answer
https://thestarman.pcministry.com/math/rec/RepeatDec.htm
9. http://www.aquatutoring.org/miscmath.php has solution as 92 not 90 as in the answer sheet
10. let BC/AB=y; larger square side a, smaller square side b
triangle area is BC*AB/2 = 1/2 y AB^2
a/AB = ay/(ay+1) = y/(y+1), so a = y/(y+1) AB
solve for y by the small triangle area 9/289
(a-b) /b = y, so b = a/(y+1)=y/(y+1)^2 AB,
1/2 b*(a-b) = 9/289 1/2 y AB^2
b/AB=3/17= y/(y+1)^2
so y = 3/17 * (y+1)^2, can solve for y
a^2/ (1/2*y*AB^2) = 2y/(y+1)^2 = 2y/(17/3*y) = 6/17 answer
2017 national team
7. can solve hot dog = 2.15, patties=4.15
.15 .30 .45 .60 .75 .9 .05 .2 .35 .5
.9 = 6, .05=7 x2=14; 14*2.15+6*4.15=55 answer
8. 1.9=19/10>1, so must have 1, then 9/10>1/2, must have 2; 4/10=2/5>1/3, must have 3,
2/5-1/3=1/15, so have 15, 1+2+3+15=21 answer
9. there are two geometric sequences, first one: 210 *3/5 (1+1/15+1/15^2+....)
second: 42*2/3(1+1/15+1/15^2+....), sum both up to get 135+30=165
zeno paradox?? went to 164.2 after 3 rounds, not to the end
10. 7 cars to 5 children
2017 national target
3. https://www.mathhomeworkanswers.org/64588/permutation
As there are two senators for each state then 100 senators can be considered as 50 pairs covering 50 states. Either senator could be picked to serve on the committee. Instead of thinking in terms of senators think in terms of state representation. There are 50C5 ways of combining the representation into a committee of 5, equal to 2,118,760 (50*49*48*47*46 divided by the number of ways of arranging 5 objects, because we are only interested in combinations, not permutations). We could pick either senator for each of the five states represented, so we need to multiply this number by 2^5=32: 67,800,320
100*98*96*94*92/5!
8.
x k m z. - 4
wxyz - 4
total 16 ways
but x and z can repeat, wxxy wxxz, wxyz, xxyz, 24+12*3=60, 60*2=120
k and m each has 24*4=96, 96*2=192
192+120=312,
wxyz repeats between x and z, 24 counted twice, 312-24=288 Answer
2017 national sprint
15. 1000 times both sides, subtract
999n/814=D75, divisible by 9, D must be 6, then n = 550
22. case work, subcase
11 12
10 12 - 9
9 12
12 11 - 45 total
10 9. -
8 7 - 5
8 6 - 1
8 5 - 1
7 6 - 5
7 5 - 1
6 5 -1
24 03 30 - 1/8 two heads 1/2;
1-2 2-1 3/8 each 2 head 1/4; 1/8+3/8*1/2=5/16;
25. drop an altitude and use pythagorean theorem to solve; or use existing median theorem
26. 25 tiles A1 A2...D5, random select 3 without replacement, prob of at least one pair having same letter or number?
method 2 - two cases
case 1: first tile doesn't matter A1; second tile has common with first C1; and third tile common with either first or second(7 of A1 then 4 of C1): 8/24*(7+4)/23=11/69
case 2: first tile doesn't matter; second tile differ from first; third tile common match with both first and second: 16/24*2/23=4/69
total = 15/69=5/23
method 1 - complementary - consider no same letter or number cases,
16/24 x 9 /23 * 3 = 18/23
1 - 18/23 = 5/23
27. similar trapezoids - ratio of sides
28. 1.75+sqrt3=(1+sqrt3/2)^2
29. x+y+z=36
x=5+y
x=2y or z=2x; or z=2y, or x=2z; y=2z
five solutions for longest length: 21 20.5 15.5 16.4 17.4
30.
method 1: small radius = tan 15 degrees;calculate tan15=tan(60-45) gives the answer
method 2: drop an altitude from intersecting point to y-axis; length 1/2, 1-sqrt3/2 gives the chord length as
sqrt(2-sqrt3), two small similar triangles gives
2r/sqrt(2-sqrt3)=sqrt(2-sqrt3) /(1/2), solves r=2-sqrt3
http://mathteamnyc.weebly.com/mathcounts.html has many years with solutions
https://wenku.baidu.com/view/102f210ff12d2af90242e6d6.html
latex symbols: