READING A TAB SEPERATED FILE IN JAVA

while ((str = in.readLine()) != null) { if (str.trim().length() == 0) { continue; } String[] values = str.split("\\t"); System.out.println("Printing file content:"); System.out.println("First field" + values[0] +

"Next field" + values[1]); }

oplossing

String[] values = str.split("\\t", -1); // don't truncate empty fields System.out.println("Printing file content:"); System.out.println("First field" + values[0] + (values.length > 1 ? ", Next field" + values[1] : " there is no second field"));

http://www.dreamincode.net/forums/topic/238109-reading-input-separated-by-tab/

import java.util.*; public class zipApp { public static void main (String[] args) { System.out.println("How many enteries will you be using?"); Scanner s = new Scanner(System.in); int length = s.nextInt(); s.nextLine(); String[] array = new String[length]; for(int x = 0; x<array.length; x++) { System.out.println("Please enter the First name, Last name, and Zip code, all separated by a tab: "); array[x]=s.nextLine(); } ZIP[] zips = new ZIP[length];

String delimiter = "\\t"; String[] temp; for(int x = 0; x<array.length; x++) { temp = array[x].split(delimiter); ZIP z = new ZIP(temp[0], temp[1], Integer.parseInt(temp[2])); zips[x] = z; } for (int x = 0; x<zips.length; x++) System.out.println(zips[x]); } } public class ZIP { String first; String last; int zip; public ZIP(String first, String last, int zip) { this.first = first; this.last = last; this.zip = zip; } public String toString() { return first+"\t"+last+"\t"+zip; } }

Een ander aangeboden oplossing

import java.util.Scanner; public class Main { public static void main( String[] args ) { new Main(); } public Main() { Scanner s = new Scanner( System.in ); System.out.println( "Enter number of individuals" ); int numb = s.nextInt(); s.nextLine(); System.out.println( "Enter individuals" ); s.useDelimiter( "[\\t\r]" ); Individual[] individuals = new Individual[numb]; for ( int i = 0; i < numb; i++ ) { String firstname = s.next(); String lastname = s.next(); int zip = s.nextInt(); s.nextLine(); individuals[i] = new Individual( firstname, lastname, zip ); } for ( Individual i : individuals ) System.out.println( i ); } public class Individual { String firstname; String lastname; int zip; public Individual( String firstname, String lastname, int zip ) { this.firstname = firstname; this.lastname = lastname; this.zip = zip; } public String toString() { return firstname + " " + lastname + " " + zip; } } }

JAVA REGULAR EXPRESSION

http://stackoverflow.com/questions/600733/using-java-to-find-substring-of-a-bigger-string-using-regular-expression

• http://www.ocpsoft.org/opensource/guide-to-regular-expressions-in-java-part-1/ - VISUAL REG TESTER
• http://www.tutorialspoint.com/java/java_regular_expressions.htm - TRY IT (mogelijkheid)
• The matches and lookingAt Methods
• http://introcs.cs.princeton.edu/java/72regular/