Loop Division Multiple Access (LDMA)

Assumptions:

1. There are 𝑛 tasks, which are circularly linked, in task queue.

2. Task 𝑖 acquires 𝑙(𝑖) loop slots in a round for 𝑖=1,…,𝑛.

Operations:

1. Task 𝑖 will execute 𝑙(𝑖) loops from 𝑖=1,…,𝑛 in order.

2. After task 𝑛 finished, the operation 1 will be repeated.

Example:

Assume that task 1 is designed to flash led1 per 0.2 seconds; task 2 is designed to flash led2 per 2 seconds. Developers can set 𝑙(1) as 10 with 0.1 second delay in a loop and 𝑙(2) as 1 with no delay in a loop. The operation of LDMA will operate as the following table.

Example Code

#include <LDMA.h>

int led1 = 4;

int led2 = 5;

void setup() {

// put your setup code here, to run once:

Serial.begin(9600);

pinMode(led1, OUTPUT);

pinMode(led2, OUTPUT);

LDMA.addTask(led1flash, 10);

LDMA.addTask(led2flash, 1);

}

void loop() {

// put your main code here, to run repeatedly:

LDMA.start();

}

void led1flash(){

digitalWrite(led1, HIGH);

delay(100);

digitalWrite(led1, LOW);

delay(100);

}

void led2flash(){

digitalWrite(led2, HIGH);

delay(1000);

digitalWrite(led2, LOW);

delay(1000);

}

Download:

Developers can clone A2MT at https://github.com/ellingtonsu/A2MT.