The parabola is the locus of a point which moves so that it is always the same distance from a fixed point (called the focus) and a given line (called the directrix).
Note:The surface of revolution obtained by rotating a parabola about its axis of symmetry is called a paraboloid.
A parabola is a curve where any point is at an equal distance from: a fixed point (the focus ), and. a fixed straight line (the directrix ) .
When the vertex of a parabola is at the ‘origin’ and the axis of symmetry is along the x or y-axis, then the equation of the parabola is the simplest. Here is a quick look at four such possible orientations:
PF = √ {(x – a)2 + y2}
Also, PB = √ (x + a)2
Since, PF = PB [from eq. (1)], we get
√ {(x – a)2 + y2} = √ (x + a)2
So, by squaring both sides, we have (x – a)2 + y2 = (x + a)2 or, x2 – 2ax + a2 + y2 = x2 + 2ax + a2 . Further, by the solving the equation, we have y2 = 4ax … where a > 0. Therefore, we can say that any point on the parabola satisfies the equation:
y2 = 4ax
let’s derive the equation for the parabola shown in Fig.2 (a). As can be seen in the diagram, the parabola has focus at (a, 0) with a > 0. Also, the directrix x = – a. Let F be the focus and l, the directrix. Also, let FM be perpendicular to the directrix and bisect FM at point O. Produce MO to X.
Latus rectum of a parabola is a line segment perpendicular to the axis of the parabola, through the focus and whose endpoints lie on the parabola as shown below.
Example: Find the coordinates of the focus, axis, the equation of the directrix and latus rectum of the parabola y2 = 8x.
Solution: the parabola equation involves y2, so the axis of symmetry is along the x-axis.
The coefficient of x is positive so the parabola opens to the right. Comparing with the given equation
y2 = 4ax, we find that a = 2.
Thus, the focus of the parabola is (2, 0) and the equation of the directrix of the parabola is x = – 2 . Length of the latus rectum is 4a = 4 × 2 = 8.
Example: Find the equation of the parabola with vertex at (0, 0) and focus at (0, 2).
Solution: Since the vertex is at (0,0) and the focus is at (0,2) which lies on y-axis, the y-axis is the axis of the parabola. Therefore, equation of the parabola is of the form x2 = 4ay.
Thus, we have x2 = 4(2)y, i.e., x2 = 8y