Solving Systems of Equations by Substitution

Each of the problems below is a link. If you click on the problem, it will take you to a YouTube video of a full, step-by-step solution for the problem. You may try these problems as practice and use the videos to check your answer, or you can just watch the videos to see more worked-out example problems.

Solve by substitution: y = 3x + 1 and x + y = 5
Solve by substitution: y = 2x + 3 and y = negative 2x + 3
Solve by substitution: x minus 2y = 4 and y minus 2x = negative 5
Solve by substitution: x + 2 = 3y and x minus 2 = 2y
Solve by substitution: y minus 4 = 2x and 4x minus 2y = negative 8
Solve by substitution: y = 1 half x + 6 and 4y minus 2x = 6