Plotting 2D and user defined I/O

OBJECTIVE:

To work on basic graphics, including 2D plots in Scilab.

ALGORITHM:

1. Define the x-axis and y-axis range.
   
   

2. Use the plot() function to plot the graph.
   
   

3. Provide a title, x-axis, and y-axis labels.
   
   

4. Use multiple plot() commands to overlay different graphs on the same plot.
   
   

5. Populate the figure window with the plot.
   
   

6. Use subplots to divide the figure window into rows or columns and plot multiple graphs.
   
   

7. Generate a pie chart using the pie() command.
   
   

SOURCE CODE:

Plotting a Single Plot:

// Defining the x-axis range

X = 0:1:10;

Y = X.^2 - 10.*X + 15;

// Plotting the graph

plot(X, Y);

// Adding title and axis labels

title("X^2 - 10X + 15");

xlabel("X");

ylabel("Y");

Multiple Plots on the Same Graph:

x = 0:1:10;

y = cos(x);

y1 = sin(x);

// Plotting both graphs on the same figure

plot(x, y, x, y1);

// Customizing the plot styles

plot(x, y, 'ys:', x, y1, 'gd--');

Subplots:

f = input('Enter the frequency: ');

a = input('Enter the amplitude: ');

t = 0:0.01:2;

y = a * sin(2 * %pi * f * t);

y1 = a * cos(2 * %pi * f * t);

y2 = t;

// Creating subplots

subplot(3, 1, 1);

plot(t, y);

subplot(3, 1, 2);

plot(t, y1);

subplot(3, 1, 3);

plot(t, y2);

Pie Chart:

// Plotting a pie chart

pie([1 2 5]);

SAMPLE INPUTS & OUTPUTS:

Plotting a Single Plot on the Graph:

// Plot will show a quadratic curve

Multiple Plots on the Same Graph:

// Plot will show cos(x) and sin(x) graphs on the same plot with different styles

Subplots:

// Input:

// Enter the frequency: 2

// Enter the amplitude: 4

Pie Chart:

// Pie chart displaying the values [1, 2, 5]

RESULT:

The two-dimensional graphs are plotted using Scilab commands.

USER DEFINED INPUT AND OUTPUT (Tank Overflow)

B]

OBJECTIVE:

To develop a program that checks whether a tank is overflowing based on its shape, dimensions, and the rate of flow (civil applications).

ALGORITHM:

1. Assume the tank is of a specific shape (rectangular, cylindrical, etc.) and define its dimensions.
   
   

2. Calculate the volume of the tank.
   
   

   • For example, for a cylindrical tank:
     Vtank=πr2hV_{\text{tank}} = \pi r^2 h where:
     
     

     • rr = radius of the tank (m)
       
       

     • hh = height of the tank (m)
       
       

3. Calculate the volume of liquid: Vliquid=F×tV_{\text{liquid}} = F \times t where:
   
   

   • FF = rate of flow (m³/min)
     
     

   • tt = time taken (min)
     
     

4. Check the overflow condition:
   
   

   • If Vliquid>VtankV_{\text{liquid}} > V_{\text{tank}} → Overflow
     
     

   • If Vliquid<VtankV_{\text{liquid}} < V_{\text{tank}} → Not Overflow
     
     

SOURCE CODE:

// User Input

F = input('Enter the Value of Flow Rate: ');

t = input('Enter the time to fill the Tank: ');

r = input('Enter the Radius of the Tank: ');

h = input('Enter the Height of the Tank: ');

// Calculating the volume of the tank

Vtank = %pi * r^2 * h;

disp('Vtank:');

disp(Vtank);

// Calculating the volume of the liquid

Vliquid = F * t;

disp('Vliquid:');

disp(Vliquid);

// Overflow check

if Vliquid > Vtank then

    disp('Tank is Overflow');

else

    disp('Tank is not Overflow');

end

SAMPLE INPUTS & OUTPUTS:

Input:

Enter the Value of Flow Rate: 10

Enter the time to fill the Tank: 2

Enter the Radius of the Tank: 3

Enter the Height of the Tank: 4

Output:

Vtank:

113.09734

Vliquid:

20

Tank is not Overflow

RESULT:

The program successfully determines if the tank is overflowing or not based on the input values.

USER DEFINED INPUT AND OUTPUT (Structural Stability of Truss)

C]

OBJECTIVE:

Write a program to determine the structural stability of a given truss.

ALGORITHM:

1. Assume a definite shape for the truss (e.g., a shape made of straight lines).
   
   

2. Determine the number of members (m) and joints (j) in the structure.
   
   

3. The stability of the truss is calculated using the formula:
   m=2j−3m = 2j - 3
   Where:
   
   

   • mm = number of members
     
     

   • jj = number of joints
     
     

4. Determine the stability:
   
   

   • If m=2j−3m = 2j - 3 → Stable (Perfect Truss)
     
     

   • If m>2j−3m > 2j - 3 → Indeterminate (Redundant Truss)
     
     

   • If m<2j−3m < 2j - 3 → Unstable (Deficient Truss)
     
     

SOURCE CODE:

// User Input

M = input('Enter the Number of Members: ');

J = input('Enter the Number of Joints: ');

// Calculate the required members for stability

N = 2 * J - 3;

// Stability check

if M == N then

    disp('The Given Structure is Stable');

elseif M > N then

    disp('The Given Structure is Indeterminate');

else

    disp('The Given Structure is Unstable');

end

SAMPLE INPUTS & OUTPUTS:

Input (Assuming a Triangle Truss):

Enter the Number of Members: 3

Enter the Number of Joints: 3

Output:

The Given Structure is Stable

RESULT:

The program calculates and displays the stability of the given truss structure based on the number of members and joints.