Embedded Files
Documents you may need:
Range of Projectile Lab (pdf or doc)
Range of Projectile ALTERNATE Lab (pdf or google doc) **Ignore this if you were present to complete the lab in class.**
PhET Projectile Lab Simulation (pdf or doc)
Lecture Notes: (You will need to be signed in to your PUSD Google account in order to download them)
Extra Practice: Projectile Practice worksheet (pdf or doc) (hints below)
1. It's a vertically shot projectile. Given that height, the time it spends in the air, and that you know what pulls it down, you can solve for the initial velocity using the magenta equation. (<3)
2. It's a horizontally shot projectile. Since you know its horizontally shot it's going to act like it was dropped in the y-direction. Use the magenta equation to solve for the time. (<0.5) With that time, use the blue equation to solve for the horizontal velocity. (<2)
**The Motion Test on Oct. 3rd will NOT have any angled projectile calculations on it; so don't worry about #3 below (focus on #1 and #2 above).**
3. Its an angle projectile. First, solve for the initial velocity in both directions. (a) With that initial vertical velocity, solve for the maximum height using the green equation. (0.2) (b) Solve for the time, you can use many equations to solve for time. (0.4) (c) With the time for the whole flight and the initial horizontal velocity you solved for in the beginning, solve for the range. (<1)
October 8th, 2015 STUDY FOR QUIZAM!
To prepare for Angled projectiles, here is a Study Guide (pdf) for Horizontally Shot and Angled Projectiles.
Homework Packet:
1. pg. 152 #7, 11; pg. 164 #34, 35, 40, 41, 43
2. pg. 164-165 #33, 42, 44, 45, 46, 52; pg. 150 #1 (skip part c), 2
3. pg. 164 #53, 58, 59
4. DWQs (4)
Homework Hints:
October 3rd, 2014 pg. 150# (skip part c), 3 and pg. 164 #52
1.a) You have enough information in the y-direction to solve for time. You know that if it was horizontally shot the initial velocity in the y-direction was zero; and you know gravity is pulling it down. Knowing how far it fell (-78.4m) you can use the purple equation to solve for the time. (<5)
b) Using that time and the initial horizontal velocity you can solve for the range using the blue equation. (~20)
2. Since you know how far it fell, that if it was horizontally shot so the initial velocity in the y-direction was zero, and you know gravity is pulling it down, use the purple equation to solve for the time. (0.5) Now that you have the time and the range or displacement in the x, you can solve for the initial horizontal velocity using the blue equation. (>1)
52. a) You have enough information in the y-direction to solve for time. You know that if it was horizontally shot the initial velocity in the y-direction was zero; and you know gravity is pulling it down. Knowing how far it fell (-1.225m) you can use the purple equation to solve for the time. (<1)
b) Given this time and the range or displacement in the x, you can solve for the initial horizontal velocity using the blue equation. (<1)
To prepare for Angled projectiles, here is a Study Guide (pdf) for Horizontally Shot and Angled Projectiles.
October 8th, 2014 pg. 152 #4, 5, 9
4. Before you do anything else, find the initial velocity in the x and y directions using sine and cosine as we did in class. Your calculator must be in degrees! (Go to "Mode" and change from rad
ians to degrees) (a) Using the initial vertical velocity (viy<14), you can use the orange equation to solve for the hang time. You can either use a final vertical velocity (vfy) of 0 m/s (which is half of the trip) and then multiply by two or you can use a final vertical velocity that is equal but opposite to the initial vertical velocity. (<3s) (b) Using the initial vertical velocity, the fact that at the maximum height the final vertical velocity is zero and that gravity is pulling it down, you can use the green equation to solve for the maximum height. (<10) (c) Using the time from (a) that the football is in the air and the initial horizontal velocity (vix>20) you can use the blue equation to solve for the range of the football. (>60)
5. Same exact set-up as #4 but because the angle has changed the initial velocity components will change too! New vix<14 and viy>20 which changes the hangtime (<5), the maximum height (<30). What do you notice about the range?
9. Since the 50 degree angle is with the vertical you will use an angle of 40 degrees for your velocity vectors. Before you do anything else, find the initial velocity in the y direction using sine as we did in class. Your calculator must be in degrees! (Go to "Mode" and change from radians to degrees) Now that you have the initial vertical velocity (viy<7) you can use the green equation to solve for the maximum height. You also know that at the maximum height the final vertical velocity is zero and that gravity is pulling it down. (>2)
56. Look at the picture below first: solve for initial vertical velocity (viy<25) using sine and initial horizontal velocity (vix>40) using cosine
a. Solve for the initial vertical velocity and then use the green equation to solve for the dy at the maximum height which means vfy is 0m/s. (>30)
b. With all the information you now have in the y-direction, you can use the orange or purple or red equation to solve for the time. Make sure the variables you use match up. If you use the information for half the trajectory, you'll get half the time so make sure you double it. (5) Once you have the time, use the blue equation to solve for the range. (>210)
October 7th, 2014 pg. 164 #53, 58, 59 and Finish Projectile Lab
53. This is a horizontally launched projectile. Use the purple equation and the given y-direction information to solve for the time (>0.5)
Given that speed in meters per second and the time you found to solve for the range using the blue equation. (<5)
58. This is a horizontally launched projectile. (a) Use the purple equation and the given y-direction information to solve for the time (>14)
(b) Convert the 125 km/hr to m/s. Given that speed in meters per second and the time you found in (a) to solve for the range using the blue equation. (<500)
59. This is a horizontally launched projectile. (a) Use the purple equation and the given y-direction information to solve for the time (<4)
(b) Given that horizontal displacement and the time you found in (a) solve for the velocity using the blue equation. (<7)
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