If x^n+-k*y^n has algebraic factorization, then x^n+-(k*m^n)*y^n has similar algebraic factorization, just replace "y" to "m*y" in these formulas, e.g. x^2-9*y^2 = (x - 3*y) * (x + 3*y) since 9 = 3^2, and x^3+8*y^3 = (x + 2*y) * (x^2 - 2*y*x + 4*y^2) since 8 = 2^3, thus we only list the k not divisible by an n-th power > 1


Only list the algebraic factorizations that include the 1st power of x and/or y, e.g. x^6+y^6 = (x^2 + y^2) * (x^4 - y^2*x^2 + y^4) only includes the 2nd and 4th powers of x and y, so not listed here, and x^8+4*y^8 = (x^4 - 2*y^2*x^2 + 2*y^4) * (x^4 + 2*y^2*x^2 + 2*y^4) only includes the 2nd and 4th powers of x and y, so not listed here, since the factorization of x^6+y^6 is similar to the factorization of x^3+y^3, just replace "x" and "y" to "x^2" and "y^2" respectively, and the factorization of x^8+4*y^8 is similar to the factorization of x^4+4*y^4, just replace "x" and "y" to "x^2" and "y^2" respectively