According to the Fourier theorem, any practical periodic function of frequencyω0 can be expressed as an infinite sum of sine or cosine functions. A periodic function satisfies:
f(t) = f(t +nT), where n is an integer and T is the period of the function
Suppose we have periodic signal f(t). The Fourier Theorem says that any practical periodic function can be expressed as a sum of sinusoidal functions of it's fundamental frequency wo.
For a function to be represented by a Fourier series, it must meet the Dirichlet conditions:
f(t) is single-valued everywhere (normal function).
f(t) has a finite number of finite discontinuities each period (not too many breaks).
f(t) has a finite number of maxima and minima in each period (not too jumpy).
The integral ∫|𝑓(𝑡)|𝑑𝑡 < ∞ for any interval of one period (doesn't blow up)
We need to basically solve a0, an, and bn
A DC component of 0V and 3V is shown to the right. Basically, a DC component moves the entire signal up or down.
Determine the Fourier series of the waveform shown below.
This is a periodic signal so f(t) = f(t +T) , where T = 2 in this case.
Use the formulas and wo = 2pi/T to solve a0, an, and bn
We have solved a0, an and bn so the solution is:
The more f(t) terms you add together , the closer the Fourier approximations gets to the original signal. When the sum goes to inf, its should exactly be the original signal. Below shows a plot of the first 11 terms of the Fourier series we solved.
A signal is Even if x(t) = x(-t)
A signal is Odd if x(t) = -x(-t)
Note that cos is an even signal and sin is an odd signal
You can use this fact to quickly estimate some common functions.
If f(t) is odd, then we expect zero pr little contribution from the cosine functions
if f(t) is even then we expect zero or little contribution from the sine functions.