The game uses film excerpts as cut scenes throughout the game at certain milestones. This footage includes clips from the original The Matrix theatrical films, and from other sources, including the short film series, The Animatrix and Enter the Matrix.

Larry Wachowski: Now, the real reason we are here is to discuss the big problem we faced in turning these three movies into a video game. You see, at this point in the story, Neo stands on the verge of satori, ready to resolve the paradox of choice and choicelessness, of free will versus fate, but that can only be achieved through an act of surrender, which occurs after he has abandoned the perspectival nature of truth, accepting the totality of present consciousness which ultimately allows an evolutionary transition, transcending the Cartesian dilemma through the emergence of delimited spirit, which then provides the world with the choice of a third path, the path of Neo, the path of peace.


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In case you're worried about whether or not you've got what it takes to lay some green-coded smack down on Agent Smith and the rest of your enemies, you can now take a chill pill right after that red pill. IGN Guides is here to give you better guidance than the Oracle to help you along this perilous path. Need to brush up on your kung-fu fighting and gun blazing acumen? Stop by Basics for a little refresher course. Want to truly enjoy the experience of walking the path of Neo? Head over to Walkthrough for, yup, a complete walkthrough. Want to delve a bit deeper into the rabbit hole? Check out Secrets for some tidbits that would make even The One say, "Whoa." Finding some of The Matrix a tad confusing at times? Who doesn't? Take a look at Q&A for a few morsels of truth. Finally, step up to Boards to talk shop about this thing called The Matrix with some of your fellow potentials.

This is part of project to calculate the remaining strength in a material. The matrix represents a grid on the material. Each cell in the matrix contains a measured parameter at a location on the grid.

There are still some questions.


1) Is the following correct: We never go to the left and we never go back (up or down) from where we came. That way endless paths are excluded



2) Where does a path end. You wrote that it spans from the first column to the last one.

2b) do we have to stop immediately when we reach the first time a cell in the last column?

In other words: Is C1-C2-C3-B3-B4-B5-B6-B7-C7 a valid path or not?



3) What should the result be? You wrote "I need to calculate the sum of all the paths available from each of the cells in column zero." What means "sum of all the paths"?


3a) Are you just interested in the number of paths possible from each of the cells in the first column. The result being a 5-element vector representing the number of paths for each of the 5 start cells.

This is probably not what you are looking for, as the values in the cells would be irrelevant and the result would be the same for any cell in the first column -> r^(c-1) if you have a r x c matrix.


3b) Do you intend to add all numbers for all paths possible from a start cell? The result being a 5-element vector and each element is the total sum of of all cell values for all paths possible from each of the 5 start cells.


3c) Similar as 3b), but this time the sum of values is listed separately for each path. That way for each start cell we would have a list of results. The result could be either represented by a nested 5-element vector and this time the elements would be vectors again, representing the cell sums of each of the 15625 paths possible from a start cell. Or you could represent the result in a 5 * 15625 matrix.

You will of course loose any information as to which path which value belongs to.

For a 20 x 40 matrix the result would be a matrix with 20 rows and 5.498*10^50 columns!! Guess this is also not what you are looking for, right?


Whatever the result should be - I think that the easiest approach would be a function which is called recursively. There is no easy, ready-made function available you could use out of the box. You will have to use some programming.


I can't read your file with my version of Prime so I can't see if you just provided a 5 x 7 matrix or if you already have tried some approach. You may consider attaching a screenshot or a pdf-print of your file in the latter case.

If you look at the formula for the number of possible paths I sent in my previous post, its no surprise that adding rows rather moderately increase the calc time but adding columns let the time explode. After all the rows are at the base, but the columns in the exponent (n = r^(c-1))

1) Is the following correct: We never go to the left and we never go back (up or down) from where we came. That way endless paths are excluded Correct. Note that diagonal moves are not permitted in any direction



2) Where does a path end. You wrote that it spans from the first column to the last one. Path ends at the last column

2b) do we have to stop immediately when we reach the first time a cell in the last column?

In other words: Is C1-C2-C3-B3-B4-B5-B6-B7-C7 a valid path or not? Not valid. You can only go one cell at a time, so from C1 you can only go to B1 or D1


3) What should the result be? You wrote "I need to calculate the sum of all the paths available from each of the cells in column zero." What means "sum of all the paths"? Each cell has the data relating to the material condition at that point. The sum of the material loss at each location on the path is averaged and then applied to a formula which gives the remaining strength. This calculation is applied for all paths.


3a) Are you just interested in the number of paths possible from each of the cells in the first column. The result being a 5-element vector representing the number of paths for each of the 5 start cells.

This is probably not what you are looking for, as the values in the cells would be irrelevant and the result would be the same for any cell in the first column -> r^(c-1) if you have a r x c matrix. It is not just the number of paths but the actual route of each of the paths that is important.


3b) Do you intend to add all numbers for all paths possible from a start cell? The result being a 5-element vector and each element is the total sum of of all cell values for all paths possible from each of the 5 start cells. Yes


3c) Similar as 3b), but this time the sum of values is listed separately for each path. That way for each start cell we would have a list of results. The result could be either represented by a nested 5-element vector and this time the elements would be vectors again, representing the cell sums of each of the 15625 paths possible from a start cell. Or you could represent the result in a 5 * 15625 matrix.

You will of course loose any information as to which path which value belongs to.

For a 20 x 40 matrix the result would be a matrix with 20 rows and 5.498*10^50 columns!! Guess this is also not what you are looking for, right? Right!


Whatever the result should be - I think that the easiest approach would be a function which is called recursively. There is no easy, ready-made function available you could use out of the box. You will have to use some programming.


I can't read your file with my version of Prime so I can't see if you just provided a 5 x 7 matrix or if you already have tried some approach. You may consider attaching a screenshot or a pdf-print of your file in the latter case. I just provided a 5 x 7 matrix with some random values in.

The question was meant to clarify if it would be valid to go down one step from B7 to C7 in the last column and as I suspected thats not a valid move as the path stops at B7 (given a 7-column matrix).

3) What should the result be? You wrote "I need to calculate the sum of all the paths available from each of the cells in column zero." What means "sum of all the paths"? Each cell has the data relating to the material condition at that point. The sum of the material loss at each location on the path is averaged and then applied to a formula which gives the remaining strength. This calculation is applied for all paths.

The routine I provided follows every possible path and given a 20 x 40 matrix this means it would have to follow 20^39 different paths which takes too long to calculate - it won't finish in a lifetime.

I haven't found a suitable iterative algorithm yet. I just developed a routine which creates matrices for every cell in the first row where every cell would indicate how many paths a cell is involved to. Using this matrices its very easy to quickly calculate the desired values.

I could imagine that a crack route has a preference for the surrounding cell with the smallest (or else the largest) value of the three (up, forward, down) cells. But I have to admit that I have no idea about the actual meaning of the matrix cell values...

But if this knowledge could be used, then a single route would result from each of the starting points, which would not only make the result matrix much shorter, but it would also calculate faster because less paths have to be investigated by the recursive routine.

Whatever you might think of the last two Matrix films, The Animatrix, Enter the Matrix, or anything else with the word Matrix in it from the last couple of years, it doesn't make The Matrix: Path of Neo any less good. Path of Neo is the second Matrix game from developer Shiny, and after the disappointing Enter the Matrix, you might be wondering why you should even bother this time around. You should, simply because Path of Neo isn't too much like its predecessor. It clearly uses some similar stylistic touches, but it's mechanically a much better game--a game that's made even better by you playing as Neo, "the One," from the beginning of his adventures right down to the conclusion of the last film...sort of. Path of Neo also takes liberties with the story in order to get it into game shape, and serious Matrix fans might be put off by how the storyline is treated so whimsically at times. You also might find yourself frustrated by how flagrantly chaotic the action can be, and we're not necessarily talking about the measure of controlled chaos the game purposely creates, either. Still, Path of Neo gets more things right than it gets wrong, and there's an entertaining brawler to be found underneath its blemishes. 2351a5e196

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