Computer Architecture
Computer Architecture
Embedded Files
Class 1
Class 1
Students are given an overview of what this course is about and how it will be conducted.
Class 2
Class 2
Slides: Introduction
Videos:
Introduction (21 mins)
Moore's Law (16 mins)
Von Neumann vs Harvard Architecture (13 mins)
Class 3
Class 3
Class 4
Class 4
Classwork
Classwork
For the code given below, assume that the values of a, b and c are in registers $17, $18 and $19 respectively. Using this information, translate the code to MIPS:
using the bne instruction (instead of the beq instruction as shown in the video)
without using a jump instruction
if (a!=b){
c=a+b;
}
else{
c=a-b;
}
Explanation
Explanation
Do NOT watch before attempting the problem: Translating "if, else" to MIPS w/out Jump Instruction
Class 5
Class 5
Slides: MIPS ISA (Slides 1-13)
Videos:
MIPS Register Convention (24 mins)
Register File: Read/Write Operations (30 mins)
Class 6
Class 6
Slides: MIPS ISA (Slides 18-22)
Notes:
Videos:
Class 7
Class 7
Slides: MIPS ISA (Slides 24-28)
Notes: Load & Store Operations
Videos:
Big Endian, Little Endian (20 mins)
Class 8: Quiz 1
Class 8: Quiz 1
Syllabus: Contents of Class 2, 3, 4, 5 & 6
Class 9
Class 9
Slides: MIPS ISA
Notes:
Videos:
Translating a for loop Using beq & slti (29 mins)
Iterating Arrays in for loops (21 mins)
Classwork
Classwork
Translate the C code snippet given below to MIPS. Assume that the base address of A is in $s5.
for (int i=5; i<25; i+=5){
if(A[i]>i){
A[i] = i+10;
}
else{
A[i] -= A[i];
}
}
Class 10
Class 10
Notes: Encoding, Decoding
Videos:
Class 11
Class 11
Slides:
MIPS ISA (continued)
Notes: Shift Operations - sll, srl
Videos:
Loading a 32-bit Constant to a Register (14 mins)
Shift Operations - sll, srl (15 mins)
Integer Multiplication and Division (9 mins)
Midterm Exam
Midterm Exam
Syllabus: Everything covered so far
Class 12: Midterm Viva
Class 12: Midterm Viva
Students are asked to explain the logical reasoning behind their midterm answers. Participation in this class is mandatory for everyone who took the midterm exam.
Class 16
Class 16
Notes: Introduction to IEEE 754 FP Representation
Videos:
Floating Point Numbers (11 mins)
IEEE754 Single Precision Floating Point Representation (37 mins)
Class 17
Class 17
Notes: IEEE 754 FP to Decimal
Slides: MIPS Floating Point Instructions
Videos:
Decimal to IEEE 754 Single Precision Review + Range (13 mins)
IEEE-754 Single Precision to Decimal (19 mins)
MIPS Floating Point Instructions (12 mins)
Assignment
Assignment
Class 19: Quiz 2
Class 19: Quiz 2
Syllabus: Addressing Modes, Stack, Performance, IEEE 754 Floating Point Representation
Class 20
Class 20
Slides: Basic MIPS Architecture
Videos:
Single Cycle Datapath (36 mins)
Multicycle Datapath (25 mins)
Classwork
Classwork
The following instructions take place in a MIPS pipeline:
lw $s2, 8($t1)
add $t3, $s2, $t2
and $s3, $t2, $s2
sw $t3, 12($t1)
addi $s4, $s3, -8
Based on the given instructions:
Identify the hazards
Resolve the identified hazards using stalls only
Resolve the identified hazards in the most efficient manner to get the lowest CPI
Final Exam
Final Exam
Syllabus: Everything covered after the midterm
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