The following video shows how to find the specific heat capacity of a metal, using a method of mixtures.
The working below shows how to treat the results afterwards.
Working - (Pause the video at 4:17 and use the values on screen in the working that follows
Use c water = 4.2 J g-1 0C-1
All heat lost by the hot metal = All heat gained by water
mc∆T(cd) = mc∆T (water)
58.953g x c x (100 - 25)0C = 100g x 4.2 J g-1 0C-1 x (25 - 22) 0C
4421.475 x c = 1260
c = 1260 / 4421.475
c = 0.28 J g-1 0C-1