Numbers 570,000s

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571,428

[Math.]  The 6-digit period of the rational number 1/7 = 0.142857142857… or 0.142857. Its multiple by 7 is 999,999.  Then,             

 142,857×n = abc,def,ghi,jkl and

abc,def+ghi,jkl = 142,857, if n  = 7t+1

abc,def+ghi,jkl = 571,428, if n  = 7t+4

abc,def+ghi,jkl = 285,714, if n  = 7t+2

abc,def+ghi,jkl = 714,285, if n  = 7t+5

abc,def+ghi,jkl = 428,571, if n  = 7t+3

abc,def+ghi,jkl = 857,142, if n  = 7t+6,

for t = 0 to 142,856, and in fact abc,edf = t. The results are digit-rotations of 142,857 and the sums of first and last 3-digit numbers are always 999.

 

571,787

[Math.]  833 = 571,787 = (–5–7+1+7+87)3.