(much more difficult!)
One type of substitution cipher isn't so simple. Sometimes the code alphabet will be in random order, and you won't be given any clue to solve the code at all! You'll have to be quite smart to crack this problem.
QAFWKA J CZ UFQ UCQWECDDM
AFURTQ, J CZ TF TFZRQJZRT
(Before we work it out, maybe you would like to take a look at these Tips for Solving Cryptograms.)
Well, first of all we have a word J, which must be either I or A. Could it be A? Well, it's followed by a two-letter word J CZ. There aren't many two-letter words that can fit after an A, so think about I instead. Hmmmm.... `I AM'! Of course.
So now we have J=I, C=A, Z=M. Let's fill them in:
QAFWKA i am UFQ UaQWEaDDM
AFURTQ, i am TF TFZRQimRT
Now think hard about those last two long words. `ViDDiam'. It looks like a name. Take a wild guess. Could it be? Yes, of course! WILLIAM SHAKESPEARE.
Now you're almost finished! You've got another 8 letters:
QhFWKh i am UFQ UaQWrallM hFUesQ, i am sF sFZeQimes IM
Now look at words which are almost complete. 'sFZeQimes' and 'sF' are a good place to start...
In fact it's simple enough from here so you can finish it
LCJL'Y WZK YVJFF YLKO PWN VJZ,