INORGANIC cHEMISTRY - III

BSCM401

To prepare Hexa Thiourea Plumbus Nitrate.

Pb(NO₃)₂ + 6 ( H₂N-CS-NH₂) → [Pb (Th)₆](NO₃)₂.3H₂O

Lead Nitrate Thiourea Hexa Thio urea plumbus nitrate

CHEMICALS USED: - Lead nitrate(6 gm), Thiourea(9 gm), Distilled water, Concentrated HNO₃.

APPARATUS REQUIRED: -Beaker, Glass Road, Glass Funnel, Filter paper, Conical Flask

Dissolve 6 gm lead nitrate Pb(NO3)2 in 20 ml H2O
In another beaker dissolve 9 grams thiourea in 30ml hot water.
Mix the two solution slowly with constant stirring.
Filter the crystals and recrystalise them by using minimum quantity of 5 ml concentrated HNO3 and hot water.
On cooling colourless crystals separates out.
Cool the solution and filter the crystals obtained.
Dry and weigh the product.

Thiourea Plumbous Nitrate.mp4

Molecular Weight of lead nitrate - 331.2 gm/mol

Molecular Weight of Hexa Thiourea Plumbus Nitrate- 841 gm/mol

If 331.2 gm of Lead Nitrate gives 841 gm of Hexa Thio Urea plumbus Nitrate,

Then 6 gm of Lead Nitrate gives …………….

1. Theoritical Yield=……………

2. Practical Yield=……………..

% Yield= Practical Yield*100/Theoritical Yield

3. % Yield=…………….

1.Is the complex output stable? Why? What is the hybridization and structure formula of this complex?

2. What is the structure formula of this urea?

3. Calculate the oxidation state of Lead in this complex.

4. What is the basic idea of this experiment? Explain how thiourea linked with Lead, and draw the structure of this complex.

5. Calculate the theoretical mass obtained for complex and the percentage of it.

6. Give the properties of thiourea.

Dr. Rajni Pania,

Assistant Professor, Chemistry

Ms. Khyati Joshi

Teaching Assitant , Chemistry

Video edited by Manan Shah

6th sem BSc chemistry student

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