Problem of the Week

The following is a compilation of all of the "Problem of the Week" questions of the 2010-11 school year.

Problem One (October 14-October 21)
 
A person is told that the the product of the ages of three siblings equal 36.  He is also told that the sum of their ages is equal to the number of the house next door.  So, this person goes next door, sees the house number and says that he does not have enough information to solve this problem and the oldest child agrees.  Now, he has enough information to determine the ages of each of the siblings.  Find the ages of all three siblings. (15 points)
 
Solution: The ages are 9,2,2.
 
Problem Two (October 21-October 28)
 
If 1=3, 2=3, 3=5, 4=4, 5=4, 6=3, 7=5, 8=5, 9=4, 10=3, 11=?, 12=?.  Find the last two numbers in the sequence. (10 points)
 
Solution: 11 and 12 are both 6.
 
Problem Three (October 28-November 4)
 
Tim and Jim can mow a lawn in 8 hours.  Jim can mow the lawn on his own in 12 hours.  In how many hours can Tim mow the lawn on his own? (10 points)

The following is a compilation of all of the "Problem of the Week" questions of the 2011-12 school year.

Problem One (September 7 - September 13)

There is a group of five friends who are having breakfast together.  All they have is one bagel, and they need to split it up between the five of them.  The good thing is that since they are
not picky about what size pieces they get, the pieces do not need to be the same size.  The only complication is that they must complete this task with only 2 perfectly straight cuts.  How
can this group of hungry friends accomplish this?