"My right to speak, your right not to listen"
Ilya Stavinsky
The mystery of the gravitational field solved
In physics, during period of XVII-XIX century, the mass was characterized by the amounts of matter (ie atoms) in its volume, which according to the opinion of the time, on the one hand determined the body's ability to resist the applied force, but on the other hand, defines its weight, i.e characterized the gravitational properties of the body. Thus, in addition to mechanical properties - the interaction of bodies - the same mass shows the force of gravity in relation to another body mass. From this it was concluded that any mass creates a gravitational field around itself, whose existence is well confirmed in practice (the prediction of the planets around the sun, the discovery of new planets, etc. ..).
During this period, the classical mechanics discovered the laws of the mechanical and the gravitational behavior of mass (where mass is dominant in determining the interaction forces between the bodies), but it could not yet get into the content of the mass and even more so in the contents of the gravitational field, ie to answer the questions: what are the atoms, why the masses of bodies creates a gravitational field in which they are attracted by, what is the gravitational field. At this stage the first our acquaintance with the matter ends , which was characterized by mass and its gravitational field.
With the discovery of atoms, which together form a mass , and their constituent particles, physicists penetrated to the content of the mass . It turned out that although the atom itself is electrically neutral, it is composed of positively and negatively charged particles: protons, neutrons, electrons. The neutron is neutral in terms of charge, but it consists of charged particles, the quarks. Despite the fact that all these particles have mass, it is at this level of the study does not play the dominant role as it was the case in classical mechanics. The dominant role in determining the behavior of charged particles transferred from the mass of the particle to its charge. In other words, the force with which the particles interact with each other no longer determined by their mass but their charge. All charged particles interact with each other through an electric field, which they form. (Here we are talking about the interaction of charged particles on the atomic level rather than at the nucleus level). Hence the logical conclusion follows that if the content of the mass is the charge, then the content of the gravitational field, which a mass forms , is a certain electric field, which is formed by the charged particles that make up the atom.
But physicists do not follow this logic. Expanding the content of an atom, they attracted to the same level and the gravitational field and thus
violated the laws of human thought, when the concepts defined on the level of the form, they brought to the level of the content of this form. In other words, the gravitational field that is defined in relation to body mass, they moved to the level of the atom.
Thus the mass and gravitational field - this is the original form of existence of matter, which physicists face first with, but its content is the charge and its electric field. But if the electric field is the content of the gravitational field, how it draws all of the body, what the electric field is this ?
The electric field of the charge
А ____________________В_________________________С Q Ев Ес
So far, we are familiar with the constant electrostatic and electromagnetic fields, which are formed by a charge at rest or in accelerated motion, respectively. Let us consider the constant electrostatic field generated by the charge Q at rest.
Suppose we have a long line AC with the points A, B and C on it, where point A is our charge + Q, which creates around itself an electric field.
Then the electric field intensity at the point B of our field is Eb, and Ec is at the point C, which is less than the electric field intensity at point B. If the charge is kept constant and the charge itself will be located at all times at point A, the electric field intensity in these points will be kept constant. On the other hand, if we move the charge along with the line, ie the position of the charge
relatively straight line AC will always remain, the tension at the points B and C will remain the same. In all these cases we
say that the charge Q generates an electrostatic field which is constant.
But if there is a constant electrostatic field, then there must be its opposite, an alternating electrostatic field. In other words, if in the example above, the electric field intensity , EB and EC, all the time will vary from some maximum to some minimum, which will be different for these points, then this field will be of a varying electrostatic field. But how to create such a field practically? There are several ways:
1. Circular rotation of the charge
2. Tesla transformer
3. Kacher Brovina
4. The polarization of an atom
5. Etc
The alternating electrostatic field in the circular rotation of the charge
A "" _____________A "_____________ А____________________В_________________________С
Q EB EC
If our line to extend to the left from point A to point A" , that is the center of a circle with a radius of A" A, and begin to rotate our charge Q, it does not matter in what plane, then the charge Q will move away from our points and then it come near them. Let us consider the electric field intensity at these points B and C under such a rotation of the charge. When the charge Q reaches a point A, it will be the most close to the points B and C, so the electric field intensity at these points will be maximum, ie is equal to Eb and Ec, respectively. With further Q rotation, our charge Q will be removed from our points and so the tension at these points will be reduced according to the formula E = Q / rr. Its lowest value they achieved when our charge will be located in a diametrically opposite point, obtained from the intersection of the circle with our line, say point A"", which is farthest from our points B and C. With a further its motion the charge Q will again approach our points, and therefore the electric field intensity at these points will again rise to its maximum. The faster we rotate the charge Q, the greater the frequency of the intensity of the field will be, and the more energy will have our field. Thus we are dealing with impulse oscillations.
The alternating electrostatic field in the circular rotation of several charges
Let us complicate our experiment. Suppose that at a distance L from the center of A" we will revolve around the second charge Q1 but at different speed. Then at the same points B and C another electric field intensities will be created, E1b and E1c, of the field Q1, which will fluctuate in the same manner as the intensity of Eb and Ec, but entirely independent of them because their frequency and amplitude of the oscillation is completely different, which are determined by the charge Q1. Now we can assume that we have an N number of such charges, which are all different from the point of view of the charge and speed of rotation. In this case, at points B and C we will have now N numbers of electric field intensities with varying frequency. But if a portion of the charges will rotate with the same velocity, in this case, their intensity will be formed according to certain rules.
The alternating electrostatic field during the rotation of electrons around the nucleus
The question arises whether there are such a point of tensions in reality? Yes, there are an electric field intensities all around us in the universe and they are created on the level of the atom where electrons spin around the nucleus, which creates an alternating electrostatic field, a description of which I gave in a circular rotation of the charge. Can you imagine the frequency of oscillation of the field formed by electrons, if the period of the electron in a hydrogen atom is 24 attoseconds (1Ats = 10 ^^ -18). It follows that every inch of the space volume has enormous energy. The same field at the atom level is created by its polarization. (See my article, "The alternating electrostatic field of Stars and Planets").
Earlier I said that any neutrally charged body M is attracted to the positive or negative charge due to the polarization of our body. Consequently, during the polarization of our neutrally charged body the later becomes charged, otherwise it is not attracted to the external positive or negative charge. This charge of our body is polarized charge, whose value can be measured as the value of the usual charge. Further, if to this body to bring the body M" with the polarized charge, then the body M will again be attracted to this external polarized body M".
In that article, I showed that any atom is polarized due to rotation of the electron around its nucleus. The period of this high polarization is roughly equal to 8 - 12 attoseconds. Since all bodies are composed of atoms, their high-frequency polarization occurs synchronously with some frequency range and thus they are attracted as in the example above with polarized body M". In other words each body is at a high frequency polarization state and therefore has a high polarized charge, which interacts only with the same charge which has the same frequency. Such polarized charge at any given point in time can be regarded as permanent, so in order to calculate roughly its value, we can use a formula of Coulomb's law.
There is another condition, which yields a high-polarization charge of the atom. We know that the result of polarization is the separation of opposite charges on opposite sides of the body. For example, all familiar with the term "parade of planets", which occurs once every 200 years. This is where all or most of the planets in the solar system are located on one side of the sun. Something similar happens at the level of the atom, where all or most of the electrons at some point in time are located on the same side of the nucleus. This occurs, for example, once in the 300-1000 rotation of the electron around the nucleus.
Now let's count this high polarized charge of attracting bodies. Suppose we have two identical bodies of m1 and m2, where each mass is 1 kg and are located at a distance of 1 meter. Since we assume that the basis of the gravitational field is an alternating polarized electrostatic field that is created by any body and that attracts the bodies, then we may assume that the force with which our two masses,M1 and M2, are attracted to, will be equal to the force of attraction of these two bodies which arises as a result of their high frequency polarization.
1. The force with which these two masses,the M1 and M2, are attracted to is given by F = G m1 m2/rr, where G - the gravitational constant , r = 1 m, hence F = 6.67 X 100 000 000 000 N.
2. But with the same force attracted our two identical bodies due to their high polarized charge. Therefore, to calculate the magnitude of this charge we use the formula F = k Qq / DD, where Q and q-values of high frequency polarized charges, which we have to calculate, D - distance between them is equal to 1 meter, and k - the Coulomb constant experimentally determined.
In our case, the charges Q and q, are equal to each other because we are talking about bodies with equal mass, so the form of Coulomb's written in a form F = k qq / DD, where q = square root of F DD / k, ie
q = square root of 6.67 x 1/1000000000 N x 1mm x 4 x 3.14 x 8,85 x 10-12 CC / (N.mm) = square root of 7414.1052 x 10-12 = 86.10519845 х 10-12 C , where x - multiplication sign.
Now we calculate the high frequency polarized charge of the Earth, using the same approach, which we used for calculation of high frequency polarized charge of our body mass m1.
1. We calculate the gravitational force of interaction between the mass of the Earth and our body mass m1, using the same form as F = G M m1/rr, but we substitute the mass m2 by the mass of the Earth, M. Then F = 6.67 х 1/100000000000 Nмм/kgkg 5,9736×1024 кг х 1kg/ 1мм =39.843912 х 10000000000000 Н
2. Since with the same force the body and the Earth are attracted to each other due to high polarization of their charges, then we can write , that F = k Qq / DD, where Q - high frequency polarized charge of the Earth, which we have to calculate, and q - high frequency polarized charge of the body m1, which we calculated earlier, D - the distance between them equal to 1 meter, and k - the Coulomb constant experimentally determined. Where Q = F x DD / kq =
39.843912 х 10000000000000 N х 1мм х 4 х 3.14 х 8,85.10-12 C2/(N.м2) / 86.10519845 х 10-12 C = 51.4855 х 10^^13 C
So we calculated with a rough approximation, the maximum of the high-frequency polarized charge of the Earth =
51.4855 х 10^^13 C, and the body mass of 1 kg has a maximum of the high-frequency polarized charge = 86.10519845 х 10-12 C. But now we can roughly calculate the high-frequency polarized charge on the atomic level, because we know the high-frequency polarized charge of the Earth and the number of atoms contained in its mass is 10^^ 50. This high-frequency polarized charge on the atomic level will be equal to 51.4855 х 10^^13 C/ 10^^50 = 51.4855 х 10^^-37 C. So this charge is in quite an acceptable range, when compared with the electron charge, equal to 1.6 10 ^^ -19. Conclusion
The existence of these high-frequency polarized charges on the atomic level, which are summarized at the level of the body, the Earth, and which create high-frequency polarized field, - create the attraction of masses of bodies and the latest attraction to the Earth. But in a first approximation, ie on the surface, this high-frequency polarized field acts as a gravitational field.
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High-frequency polarized charge of the Earth = 51.4855 x 10 ^^ 13 C
High-frequency electron charge polyarizirovanny = 1.6 10 ^^ -19 C
The number of atoms in the Earth - 10 ^^ 50
The number of electrons in C - 625 10 ^ ^ 16
Diameter core - 10 ^^ -15
Charge of an electron - 1.6 10 ^^ -19
The mass of the Earth - 5,9736×1024 kg
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