backloop.py i=10 while i>0: i=i-1 print i This program, if run in terminal, will countdown from the number 10. It lists in reverse order because of the third line: "i=i-1". To make is run through from least to greatest all one has to do is change the '-' to a '+'. total.py i=0 t=0 while i<5: i=i+1 t=t+i print t This program as two variables. This is the complex thing I have written so far (lulz). It adds 1+2+3+4+5 in order to get 15. Since i starts at 0, the first time line 4 is processed, i is equivalent to 1. The program continues this opperation until i is 5. The variable 't' is in place to keep track of all the times the variable 'i' is added up. So through the course of 'i' being added 5 times, 't' reflects that total sum is 15. |