Ans.

 

2.   The correct stability order for the following species is    

(A)       (II) > (IV) > (I) > (III)

(B)       (I) > (II) > (III) > (IV)

(C)       (II) > (I) > (IV) >(III)

                  (D)       (I) > (III) > (II) > (IV)

Ans.

Most stable as it has 5 H for hyper conjugation

2 H available for hyper conjugation.

It has 6 H for hyper conjugation but oxygen being EWG destabilizes carbonation.

It is least stable as it has only 3 H for hyper conjugation as well as EWG (oxygen).

 

3.   In the following reaction sequence, the correct structures of E, F and G are 

 

Ans.

 

4.   Among the following, the surfactant that will from micelles in aqueous solution at the lowest molar concentration at ambient condition is

Ans.  CMC is lowest for surfactants having higher/longer hydrocarbon chains (which increases the tendency of the surfactant molecule to associate)

 

5.   Electrolysis of dilute aqueous NaCI solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H₂ gas at the cathode is (1 Faraday = 96500 C mol^-1)

Ans. 

 

6.   Solubility product constants (K_sp) of salts of types MX, MX₂ and M₃X at temperature “T” are 4.0 X 10 ^-8 , 3.2 X 10^-14 and 2.7 X 10^-15 respectively. Solubilities (mol dm^-3) of the salts at temperature “T” are in the order

(A)       MX > MX₂ > M₃X                  (B)       M₃X > MX₂ > MX

                  (C )      MX₂ > M₃X > MX                  (D)       MX> M₃X >MX₂

7.   Among the following, the coloured compound is

(A) CuCl      (B)        K₃ [Cu(CN)₄]

                  (C ) CuF₂    (D)        [Cu (CH₃CN)₄] BF₄

Ans. 

Cu⁺ : [Ar] 3d¹⁰ No electron transition possible (Diamagnetic) Cu²⁺ : [Ar] 3d⁹   Paramagnetic

 

8.   The IUPAC name of [Ni (NH₃)₄] [NiCl₄] is

(A)     Tetrachloronickel (II ) - teraamminenickel ( II )

(B)      Teraamminenickel (II ) - tetrachloronickel ( II )

(C)      Traamminenickel (II ) - tetrachloronickelate ( II )

                  (D)  Tetrachloronickel (II ) - teraamminenickelate ( 0 )

Ans.  [Ni(NH₃)₄] =>cation  [Nicl₄] => Anion [Note : This can never be anion]=> tetra ammine nickel (II) – tetra chloronickelate (II)

 

9.   Both [Ni (CO)₄ ] and [Ni (CN)₄]^2- are diamagnetic. The hybridizations of nickel in these complexes, respectively  are

(A)   sp³ , sp³                        (B)        sp³, dsp²

(C ) dsp², sp³                       (D )       dsp², dsp²         

Ans.

 

 

10.    STATEMENT-1 : The geometrical isomers of the complex [M (NH₃)₄ CI₂] are optically inactive.

And

STATEMENT-2 : Both geometrical isomers of the complex [M (NH₃)₄ CI₂] possess axis of symmetry.

 

(A)    STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1

(B)    STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C)    STATEMENT-1 is True, STATEMENT-2 is False

(D)    STATEMENT-1 is False, STATEMENT-2 is True

Ans. 

Trans isomer: Optically inactive as it has a plane of symmetry.

Cis isomer: It also has a plane of symmetry. So, it is optically inactive.

(B)     STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C )    STATEMENT-1 is True, STATEMENT-2 is False

(D)     STATEMENT-1 is False, STATEMENT-2 is True

 Ans.  2^nd law of thermodynamics: Heat cannot be converted to work with 100% efficiency but the reverse is not true.

(B)     STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C )    STATEMENT-1 is True, STATEMENT-2 is False

(D)     STATEMENT-1 is False, STATEMENT-2 is True

Ans. 

(B)     STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

(C )    STATEMENT-1 is True, STATEMENT-2 is False

(D)     STATEMENT-1 is False, STATEMENT-2 is True                                                                                                                                            

Ans.  [Fe (H₂O)₅ NO]  SO₄

No has a tive charge on it (NO⁺   Nitrosonium)

=> Oxidation state of Fe is +1 = Fe⁺ [Ar] 3d⁶ 4s¹ => 3 unpaired e^-s (Paramagnetic)

Paragraph for Question Nos. 14 to 6

A tertiary alcohol H upon acid catalysed dehydration gives a product I. Ozonolysis of I leads to compounds J and K. Compound J upon reaction with KOH gives benzyl alcohol and a compound L, whereas K on reaction with KOH gives only M.

 

 

                 

 

Ans. 

 

15.   The Structure of compound I is

               

 

Ans. 

 

16.   The structures of compounds J, K and L respectively are

(A)  PhCOCH₃, PhCH₂COCH₃ and PhCH₂COO^-K⁺    

(B)  PhCHO, PhCH₂CHO and PhCOO^-K⁺                   

(C ) PhCOCH₃, PhCH₂CHO and CH₃COO^-K⁺

                  (D ) PhCHO, PhCOCH₃ and PhCOO^-K⁺

Ans. 

Paragraph for Question Nos. 61 to 63

In hexagonal systems of crystals, a frequently encountered arrangement of atoms is described as a hexagonal prism. Here, the top and bottom of cell are regular hexagons and three atoms are sandwiched in between them. A space- filling model of this structure, called hexagonal close- packed (HCP), is constituted of a sphere on a flat surface surrounded in the same plane by six identical spheres as closely as possible. There spheres are then placed over the first layer so that they touch each other and represent the second layer. Each one of these spheres touches three spheres of the bottom layer. Finally, the second layer is covered with a third layer that is identical to the bottom layer in relative position. Assume radius of every sphere to be ‘r’

17.   The number of atoms in this HCP unit cell is

(A)              4          (B)        6          (C )       12                     (D)        17

Ans. 

No, of atoms in HCP

(Probability = 1) (No. of B atoms = 3) (6 in each layer = 12) (Probability =1/6, 1/2) (Centre atoms = 2)

18.   The volume of this HCP unit cell is

Ans. 

19.   The empty space in this HCP unit cell is

                (A) 74%          (B) 47.6%       (C) 32%          (D) 26%

Ans. 

20.   Match the compounds in Column I with their characteristic test(s)/ reaction(s) given in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 X 4 matrix given in the ORS.

          

Ans.  (A) Became of cl^- ion => ppt. With AgNO₃ (wite) => Agcl

Forms hydrazone Ans. (r, s)

(B) It will test for “N” as Nitrogen is attached to “C”  (p)

It will give test with Fecl₃ as it contains phenolic group.  (q)        Ans. : (p, q)

(C) As explained above, it should react [give test] for         Ans. : (p, q, r)

 

         

Ans.  (A) Orbital Angular Momentum  Azimuthal Quantum Number    Ans : q

 

(B) H - like one - e^- wave function obeying Pauli principle  Not more than 2e^-s in an orbital => spin Quantum Number.    Ans : s

 

(C)  Shape :       l          => Azimuthal Quantum Number

 size :               n          => Principal Quantum Number

Orientation :      m         => Magnetic Quantum Number

Ans. : (p, q, r)

 

(D) Probability density of e^- at the nucleus : => Principal Quantum Number.

Ans. (p)

 

22.   Match the conversions in Column I with the type(s) of reaction(s) given in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 X 4 matrix given in the ORS

Ans.  2 pbs + 3O₂2 pbO + 2 sO₂    (Roasting)   Ans. : (p)

CaCO₃CaO     (Calcination)   Ans : (q)

Ans : (p, r)         2 Zns + 3O₂Cn₂O + 2 sO₂   (Roasting)

                        ZnO + c Zn + CO                 (Carbon Reduction)

Ans : (p, s)        2 Cu₂s + 3 O₂ Cu₂O + 2 sO₂ (Roasting)

                        2Cu₂O + Cu₂s6 Cu + sO₂      (self Reduction)